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lisabon 2012 [21]
3 years ago
10

9. If the musician hit the drum on a stage, how would the sound wave behave differently if he hit it the drum if the drum were s

ubmerged in a swimming pool? You may use pictures to help with your explanation. Be very thorough with your answer! If you use any sources other than your brain to help you with this question, be sure to list them!
Physics
1 answer:
egoroff_w [7]3 years ago
4 0
I think it would be yes because the drum is submerged in water and the water would slow the sound waves, making the sound softer. Right?
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A student sits atop a platform a distance h above the ground. He throws a pingpong ball horizontally with a speed v. However, a
Nikitich [7]

Answer:

Explanation:

The pingpong ball reaches the ground directly under the student. That means net displacement is zero

Time of fall  t = \sqrt{\frac{2h}{g} }

Initial horizontal velocity = v ,

horizontal acceleration = - a ( deceleration because net displacement is zero)

0 = ut - 1/2 a t²

0 = v\times\sqrt{\frac{2h}{g} } - \frac{1}{2}a \frac{2h}{g}

v = 1/2 a \sqrt{\frac{2h}{g}

h = \frac{2gv^2}{a^2}

8 0
3 years ago
How many newtons of force are required to move a 54.87 kg object with an acceleration of 9.8 m/s/s?
vodka [1.7K]
Force equals mass*acceleration
F = ma

Given m = 54.87 kg, a = 9.8 m/s^2

F = (54.87)(9.8)
F = 537.726
F = 538 N

A force of al least 538 Newtons is required to move the object.
7 0
3 years ago
A spring has a spring constant of 53N/m. How much elastic potential energy is stored in the spring in the spring when it is comp
IRISSAK [1]

Answer:11686.5 joules

Explanation:

elastic constant(k)=53N/m

extension(e)=21m

Elastic potential energy=(k x e^2)/2

Elastic potential energy=(53 x (21)^2)/2

Elastic potential energy=(53x21x21)/2

Elastic potential energy=23373/2

Elastic potential energy=11686.5

Elastic potential energy is 11686.5 joules

5 0
3 years ago
The viewing screen in a double-slit experiment with monochromatic light. Fringe C is the central maximum. The fringe separation
makvit [3.9K]

Answer:

<em>Part A</em><em>:</em>

a) If the wavelength of the light is decreased the fringe spacing Δy will decrease.

<em>Part B</em><em>:</em>

b) If the spacing between the slits is decreased the fringe spacing Δy will increase.

<em>Part C</em><em>:</em>

a) If the distance to the screen is decreased the fringe spacing will decrease.

<em>Part D</em><em>:</em>

The dot in the center of fringe E is 920\ x\ 10^{-9} m farther from the left slit than from the right slit.

Explanation:

In the double-slit experiment there is a clear contrast between the dark and bright fringes, that indicate destructive and constructive interference respectively, in the central peak and then is less so at either side.

The position of bright fringes in the screen where the pattern is formed can be calculated with

                      \vartriangle y =\frac{m \lambda L}{d}

                      m=0,\pm 1,\pm 2,\pm 3,.....

  1. m is the order number.
  2. \lambda is the wavelength of the monochromatic light.
  3. L is the distance between the screen and the two slits.
  4. d is the distance between the slits.
  • Part A:  a) In the above equation for the position of bright fringes we can see that if the wavelength of the light \lambda is decreased the overall effect will be that the fringes are going to be closer. That means that the fringe spacing Δy will decrease.
  • Part B:  b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
  • Part C:  a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.
  • Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at  the center of the fringe E in the screen we use the condition for constructive interference. That says that the  path length difference Δr between rays coming from the left and right slit must be \vartriangle r=m \lambda

        We simply replace the values in that equation :

                      \vartriangle r= m \lambda =2.\ 460\ nm

                      \vartriangle r= 920\ x\ 10^{-9} m

         The dot in the center of fringe E is 920\ x\ 10^{-9}m farther from the left slit than from the right slit.

     

       

       

     

3 0
3 years ago
What force must act on a 50.0-kg mass to give it an ancceleration of 0.30 m/s^2?
ratelena [41]

Answer:

15.0 N

Explanation:

see pic

3 0
3 years ago
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