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3 years ago

How would you present weight change if earth had twice the mass that it does now

1 answer:

4 0

Twice the mass means twice the acceleration due to gravity which will increase acceleration by the factor of 2 thus the weight will be double the time.

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When an automobile moves with constant speed down a highway, most of the power developed by the engine is used to compensate for

uysha [10]

Answer:

F=5449 N

Explanation:

Work done is a product of force and displacement ie

Work done, W, = Force*Displacement

Power, P, is Work done/Time

$P=\frac {W}{t}=\frac {FS}{t}$ where P is power, W is work done, F is force, S is displacement and t is time

In this case, F is the frictional force. Converting the power from hp to W, we multiply by 746 hence P=746*168=125328 W

Since displacement/time is velocity, then

P=FV where V is velocity in m/s

Making F the subject

$F=\frac {P}{V}$

$F=\frac {125328}{23}=5449.043478 N$

F=5449 N

7 0

3 years ago

You have a motion security light by your door cat runs across the in the light turns on what is the input of the system and what

Neporo4naja [7]

A motion security line is a system that is used to detect motion.
The input for the system is MOTION and the output is LIGHT. That is, when the system detects motion it switch on light.
Remember, an Input is the information that was inserted into a system while the output is the result of the processed information.

5 0

3 years ago

The s.I unit of R so that the equation velocity= R × density S dimensionally correct R is a constant

Leviafan [203]

Answer:

R = m⁴/kg . s

Explanation:

In this case, the best way to solve this is working with the units in the expression.

The units of velocity (V) are m/s

The units of density (d) are kg/m³

And R is a constant

If the expression is:

V = R * d

Replacing the units and solving for R we have

m/s = kg/m³ * R

m * m³ / s = kg * R

R = m * m³ / kg . s

This should be the units of R

Hope this helps

5 0

3 years ago

A wagon is pulled at a speed of 0.40metets/seconds by a horse exerting an 1,800 Newton's horizontal force. what is the power of

Tatiana [17]

Given:

speed of 0.40meters/seconds

1,800 Newton's horizontal force

Required:

Power of the horse

Solution:

P = F(D/T) where P is power in watts, F is the force, D is the distance and T is time

P = (1,800N) (0.40 meters/seconds)

P = 720 Watts

6 0

3 years ago

Set local ground level to 700 ft, and record the inches of mercury.

pashok25 [27]

The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

<h3>How to determine the altimeter reading?</h3>

The given parameters are:

Ground level = 700 ft i.e. the field elevation
Pressure altitude = 1450 ft

The formula to calculate the pressure altitude is:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

Substitute the known values

1450 = (29.92 - Altimeter reading) * 1000 + 700

Evaluate the like terms

750 = (29.92 - Altimeter reading) * 1000

Divide both sides by 1000

0.75 = 29.92 - Altimeter reading

Evaluate the like terms

Altimeter reading = 29.17

Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg