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weqwewe [10]
3 years ago
9

How many of each component are shown in the diagram? Check all that apply.

Physics
1 answer:
g100num [7]3 years ago
3 0

Can you show the diagram please

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If you exert a force of 500 n to walk 4 m up a flight of stairs in 4 s, how much power do you use?
kobusy [5.1K]
 <span>P= work/time and work is = to force x distance so its 500x4 =2000joules 
and 2000/4 =500 watts</span>
3 0
3 years ago
A river has a steady speed 0.500 m/s. A student swims upstream a distance of1.00 km and swims back to the starting point. a) If
matrenka [14]

1.2 in still water would be 1.2-0.5 upstream

0.7 ups

1.7 downs

5 0
4 years ago
Find the speed required to throw a ball straight up and it return 6 seconds later. Neglect air resistance
Nadya [2.5K]

Answer:

the ball will go up 3s and down 3s

v=gt

where t=3s and g=9.8m/s^2

distance=v0(t)+(1/2)gt^2

where initial velocity (v0)=0

Explanation:

8 0
3 years ago
The absolute pressure in water at a depth of 5m is read to be 145 kPa. Determine (a) the local atmospheric pressure, and (b) the
irga5000 [103]

Answer:

a) 95950 pascals

b) 137642.5 pascals

Explanation:

The absolute pressure (Pabs) on a fluid is:

P_{abs}=P_{gauge}+P_{atm} (1)

With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:

P_{gauge}=\rho gh (2)

with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:

P_{atm}=P_{abs}-P_{gauge}=P_{abs}-\rho_{water} gh

P_{atm}=(145000Pa)-(1000\frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})(5m)

P_{atm}=95950Pa

b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

S.G=\frac{\rho_{fluid}}{\rho_{water}}

\rho_{liquid}=S.G*\rho_{water}

\rho_{liquid}=(0.85)*(1000\frac{kg}{m^{3}})=850\frac{kg}{m^{3}}

so:

P_{abs}=\rho_{liquid} gh+P_{atm}=(850\frac{kg}{m^{3}})(9.81\frac{m}{s})(5m)+95950Pa

P_{abs}=137642.5 Pa

3 0
3 years ago
A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel
siniylev [52]

Answer:

Explanation:

Velocity will be equal to the area under the curve of the acceleration-time plot.

v = ½(45)(0.075) = 1.6875

v = 1.7 m/s

h = (0² - 1.6875²) / (2(-9.8)) =  0.145288...

h = 15 cm

3 0
3 years ago
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