<span>P= work/time and work is = to force x distance so its 500x4 =2000joules
and 2000/4 =500 watts</span>
1.2 in still water would be 1.2-0.5 upstream
0.7 ups
1.7 downs
Answer:
the ball will go up 3s and down 3s
v=gt
where t=3s and g=9.8m/s^2
distance=v0(t)+(1/2)gt^2
where initial velocity (v0)=0
Explanation:
Answer:
a) 95950 pascals
b) 137642.5 pascals
Explanation:
The absolute pressure (Pabs) on a fluid is:
(1)
With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:
(2)
with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:



b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:



so:


Answer:
Explanation:
Velocity will be equal to the area under the curve of the acceleration-time plot.
v = ½(45)(0.075) = 1.6875
v = 1.7 m/s
h = (0² - 1.6875²) / (2(-9.8)) = 0.145288...
h = 15 cm