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belka [17]
2 years ago
10

A circuit is:

Chemistry
1 answer:
ratelena [41]2 years ago
7 0

Answer:

A. the path for the movement of charge.

Explanation:

A circuit is the path for the movement of charge.

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If a solution containing 45.101 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of s
AnnyKZ [126]

Answer:

14.533 grams of solid precipitate of mercury(II) dichromate will form.

Explanation:

Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)

Moles of mercury(II) acetate = \frac{45.101 g}{318.70 g/mol}=0.14152 mol

Moles of sodium dichromate = \frac{12.026 g}{261.97 g/mol}=0.045906 mol

According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

\frac{1}{1}\times 0.045906 mol=0.045906 mol of mercury(II) acetate

This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.

According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

\frac{1}{1}\times 0.045906 mol=0.045906 mol of mercury(II) dichromate

Mass of 0.045906 moles of mercury(II) dichromate:

0.045906 mol × 316.59 g/mol = 14.533 g

14.533 grams of solid precipitate of mercury(II) dichromate will form.

3 0
3 years ago
The rate constant for a first order reaction
Lena [83]

Answer:

E_a = 103.626 × 10³ KJ/mol

Explanation:

Formula to solve this is given by;

Log(k2/k1) = (E_a/2.303R)((1/T1) - (1/T2))

Where;

k2 is rate constant at second temperature

k1 is rate constant at first temperature

R is universal gas constant

T1 is first temperature

T2 is second temperature

We are given;

k1 = 2.8 × 10^(-3) /s

k2 = 4.8 × 10^(-4) /s

R = 8.314 J/mol.k

T1 = 60°C = 333.15 K

T2 = 45°C = 318.15 K

Thus;

Log((4.8 × 10^(-4))/(2.8 × 10^(-3))) = (E_a/(2.303 × 8.314))((1/333.15) - (1/318.15))

We now have;

-0.76592 = -0.00000739121E_a

E_a = -0.76592/-0.00000739121

E_a = 103.626 × 10³ KJ/mol

8 0
3 years ago
Which one is one pkease?
matrenka [14]

\qquad\qquad\huge\underline{{\sf Answer}}

The Correct choice is D. Fe + S = FeS

because, in nature Iron (Fe) and Sulphur (S) are found in mono - Atomic form. so, There will be 1 Fe atom reacting with 1 S atom to form FeS (Iron sulphide)

8 0
1 year ago
What is the mass of 0.7891 mol of ferric oxide (Fe,O3)?
Aleksandr [31]

Answer:

The answer to your question is letter B.

Explanation:

Process

1.- Calculate the molecular mass of Ferric oxide

Fe = 56g x 2 = 112 g

O  = 16 x 3 = 48 g

Mass = 112 + 48 = 160 g

2.- Calculate the mass of 0.7891 moles of Ferric oxide

                                160 g of Fe₂O₃ ------------- 1 mol

                                x                        ------------- 0.7891 mol

                                x =  (160 x 0.7891) / 1

                               x = 126.2 g

3 0
3 years ago
Read 2 more answers
The minimum amount of energy that particles must have in order to react is known as the... what?
Anika [276]
Activation energy

Hope this helps
4 0
3 years ago
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