Answer:
The answer to your question is: 3.745 x 10 ²³ atoms
Explanation:
Data
density = 8.96 g/cm³
mass = 29.54 g
atomic radius = 1.28 A° 1.28 x 10⁻¹⁰ m
Volume of a cube
density = mass / volume
volume = mass / density
volume = 29.54 / 8.96
volume = 3.29 cm³
Volume of a copper atom
volume = (4/3) πr³
volume = (4/3) π (1.28 x 10 ⁻⁸)³
= 8.784 x 10 ⁻²⁴ cm³
Number of atoms = 3.29 cm³ / 8.784 x 10 ⁻²⁴ cm³
= 3.745 x 10 ²³ atoms
Answer : The concentration of
ion is, 
Solution : Given,
pH = 4.20
First we have to calculate the pOH.
As we know that,




Now we have to calculate the concentration of
ion.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![9.8=-\log [OH^-]](https://tex.z-dn.net/?f=9.8%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=1.58\times 10^{-10}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.58%5Ctimes%2010%5E%7B-10%7DM)
Therefore, the concentration of
ion is, 

<h3>Further explanation</h3>
Given
3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,
Required
the new volume
Solution
Combined with Boyle's law and Gay Lussac's law

T₁ = 39 + 273 = 312
T₂ = 16 + 273 = 289
Input the value :
V₂ = (P₁V₁.T₂)/(P₂.T₁)
V₂ = (99 x 3000 x 289)/(45.5 x 312)
or we can write it as:
V₂ = 3000 L x (289/312) x (99/45.5)