<span>v/2
This is an exercise in the conservation of momentum.
The collision specified is a non-elastic collision since the railroad cars didn't bounce away from each other. For the equations, I'll use the following variables.
r1 = momentum of railroad car 1
r2 = momentum of railroad car 2
x = velocity after collision
Prior to the collision, the momentum of the system was
r1 + r2
mv + m*0
So the total momentum is mv
After the collision, both cars move at the same velocity since it was non-elastic, so
r1 + r2
mx + mx
x(m + m)
x(2m)
And since the momentum has to match, we can set the equations equal to each other, so:
x(2m) = mv
x(2) = v
x = v/2
Therefore the speed immediately after collision was v/2</span>
Answer:
The impala pushed down the ground with a force of 37.49N
Explanation:
The force at which the impala pushed down the ground can be calculated for using the Newton's second law of motion,
Force = mass × acceleration
Force = mass ×(velocity/time)
Given mass = 25.5kg
Time = 0.21seconds
To get the velocity, we will use one of the equation of motions;
Using v² = u²+2gH
where;
H is the height reached from the ground = 2.5m
g = 9.81m/s²
u is the initial velocity = 0m/s
v is the final velocity=?
Substituting this values to get the final velocity v;
v² = 0²+2(9.81)(2.5)
v² = 49.05
v = √49.05
v = 7.0m/s
Substituting this velocity into the formula for force we have;
Force = 25.5×(7.0/0.21)
Force = 25.5 × 1.47
Force = 37.49N
The impala pushed down the ground with a force of 37.49N
Answer:
Q = 836.4 Joules.
Explanation:
Given the following data;
Mass = 100 grams
Initial temperature = 25°C
Final temperature = 45°C
We know that the specific heat capacity of water is equal to 4.182 J/g°C.
To find the quantity of heat;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 45 - 25
dt = 20°C
Substituting the values into the equation, we have;
Q = 836.4 Joules.