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2 years ago

13

Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe

is 150cm²

1 answer:

ddd [48]2 years ago

8 0

Answer:

40 Kpa

Explanation:

150 cm2 = 0.015 m2

$p \: = \frac{mg}{ a} = 40000$

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Calcular la aceleración que produce una fuerza de 40 N sobre un cuerpo con 88 Kg de masa. Expresar el resultado en m⁄s^2 *

tigry1 [53]

Answer:

a = 0.45 m/s²

Explanation:

The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".

Given that,

Force, F = 40 N

Mass of the body, m = 88 kg

The net force acting on the body is given by :

F = ma

Where

a is the acceleration of the body

$a=\dfrac{F}{m}\\\\a=\dfrac{40\ N}{88\ kg}\\\\a=0.45\ m/s^2$

So, the required acceleration is 0.45 m/s².

4 0

3 years ago

Rank in order, from smallest to largest, the six torques (torque 1 to torque 2) about the hinge.?

anzhelika [568]

The solution for this problem is:torque1 = torque2 = FL / 2
Torque 3 = Torque 4 = FL / 2 * sin (theta)
Torque 5 = 2 FL
Torque 6 = 0

So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.

Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.

5 0

3 years ago

A wire of Nichrome (a nickelâ€“ chromiumâ€“ iron alloy commonly used in heating elements) is 1.0 m long and 1.0 mmÂ² in cross-se

Lyrx [107]

Answer:

The conductivity of Nichrome is $2\times 10^6\ S/m$ .

Explanation:

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:

$R=\frac{V}{A}=\frac{2.0}{4.0}=0.5\ \Omega$

Now, resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:

$R=\rho\frac{L}{A}$

Where, $\rho\to resistivity\ of\ Nichrome$

Now, plug in all the values given and solve for $\rho$ . This gives,

$0.5\ \Omega=\rho\frac{1.0\ m}{1\times 10^{-6}\ m^2}\\\\\rho=\frac{0.5\times 1\times 10^{-6}}{1.0}=0.5\times 10^{-6}\ \Omega-m$

Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

$\sigma=\frac{1}{\rho}=\frac{1}{0.5\times 10^{-6}}=2\times 10^6\ S/m$

Conductivity is measured in Siemens per meter (S/m)

Therefore, the conductivity of Nichrome is $2\times 10^6\ S/m$ .

7 0

2 years ago

HOW do I find 25? *picture included* plz answerrr

pogonyaev

Subtract all numbers to your answer

3 0

3 years ago

A uniform magnetic field of magnitude 0.72 T is directed perpendicular to the plane of a rectangular loop having dimensions 8.2

Liono4ka [1.6K]

Answer:

Explanation:

Magnetic flux is expressed as the product of magnetic field and cross sectional area.

Φ = BAsintheta

Given

B = 0.72T

A = 8.2cm×14cm

A = 0.082m × 0.14m

Area = 0.01148m²

Theta = 90°

Substitute into the formula

Φ = BAsintheta

Φ = 0.72(0.01148)sin90°

Φ = 0.72(0.01148)(1)

Φ = 0.0082656

Hence the magnetic flux through the loop is 8.2656 × 10^-3 Weber

8 0

3 years ago