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Dennis_Churaev [7]
3 years ago
14

What is the voltage drop across the 30 ohm resistor?

Physics
1 answer:
Jlenok [28]3 years ago
5 0
B - the voltage drop is 60 V
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Simon is riding a bike at 12 km/h away from his friend Keesha. He throws a ball at 5 km/h back to Keesha, who is standing still
pychu [463]
So there are different ways this could be solved. I'll do try to explain it the way I was taught... 

Simon is riding his bike at 12 km/hr relative to the sidewalk, away from where Keesha is.

Simon throws the ball at Keesha, at 5 km/hr. 

Keesha sees the ball approaching her at (12-5) = 7 km/hr relative to the ground to her. 

Therefore the answer is: 7 km/hr


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3 years ago
Which would be the best way to represent the concentration of a 1.75 M K2CrO4 solution
AlekseyPX
1.75 moles per litre K2CrO4
7 0
4 years ago
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A hockey puck of mass m1=165 g slides from left to right with an initial velocity of 15.5 m/s. It collides head on with a second
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Answer:

it may be -6 m/s

Explanation:

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The dosage of technetium-99m for a lung scan is 20. μCi /kg of body mass. How many millicuries of technetium-99m should be given
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7 0
3 years ago
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air
MArishka [77]

This question involves the concepts of work done, pressure, and temperature.

The work done per mol of the air is "-724.71 J/mol".

Using the given formula for work done:

W=RTln\frac{P_1}{P_2}

where,

W = work done per mol = ?

R = universal gas constant = 8.314 J/mol.k

T = absolute temperature = 30°C + 273 = 303 k

P₁ = initial pressure = 30 KPa

P₂ = final pressure = 40 KPa

Therefore,

W= (8.314\ J/mol.k)(303\ k)ln\frac{30\ KPa}{40\ KPa}\\

<u>W = -724.71 J/mol</u>

<u></u>

Learn more about pressure here:

brainly.com/question/23358029?referrer=searchResults

7 0
3 years ago
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