Given: Work W = 3,500 J; Force f = 250 N; Weight w = 765 N
Required: Distance d = ?
Formula: Work = force x distance or W = f x d
Distance d = W/f
d = 3,500 J/250 N
d = 14 m
Answer:
![30.4^{\circ}](https://tex.z-dn.net/?f=30.4%5E%7B%5Ccirc%7D)
Explanation:
Refraction occurs when a ray of light passes from a medium into another medium. In this situation, the ray of light bends and changes speed, according to Snell's Law:
where
is the index of refraction of the 1st medium
is the index of refraction of the 2nd medium
is the angle of incidence (the angle between the incident ray and the normal to the boundary)
is the angle of refraction (the angle between the refracted ray and the normal to the boundary)
In this problem, we have:
is the index of refraction of air
is the index of refraction of water
is the angle of incidence in air
Solving for
, we find the angle of refraction in water:
![\theta_2=sin ^{-1}(\frac{n_1}{n_2}sin \theta_1)=sin^{-1}(\frac{1.00}{1.33}sin42.3^{\circ})=30.4^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_2%3Dsin%20%5E%7B-1%7D%28%5Cfrac%7Bn_1%7D%7Bn_2%7Dsin%20%5Ctheta_1%29%3Dsin%5E%7B-1%7D%28%5Cfrac%7B1.00%7D%7B1.33%7Dsin42.3%5E%7B%5Ccirc%7D%29%3D30.4%5E%7B%5Ccirc%7D)