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slava [35]
3 years ago
11

If the temperature of a liquid increases, the density of the liquid decreases because the particles move farther apart. What are

the variables in her hypothesis?
Physics
1 answer:
Lorico [155]3 years ago
8 0

This question is incomplete because part of the content is missing; here is the complete question:

Ingrid wrote the hypothesis below.  If the temperature of a liquid increases, the density of the liquid decreases because the particles move farther apart.

What are the variables in her hypothesis?

A. The independent variable is the temperature, and the dependent variable is the density.

B. The independent variable is the density, and the dependent variable is the temperature.

C. The independent variable is the temperature, and the dependent variable is the distance between particles.

D. The independent variable is the distance between particles, and the dependent variable is the temperature.

The answer to this question is A. The independent variable is the temperature, and the dependent variable is the density.

Explanation:

To begin, the variables in an experiment are the factors being studied or analyzed, which are expressed in the hypothesis. According to this, the two variables in the experiment are the temperature and the density.

Additionally, in experiments, it is common one of the variables is independent, which is the factor manipulated by the researcher, and the other is dependent as this is expected to be changed by the first variable. If this is applied to the experiment described, the temperature is independent because this will be manipulated by Ingrid to prove density changes. Also, the density is expected to be affected by the first variable, and therefore density is the dependent variable.

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Answer:

the speed of the waves is 150 cm/s

Explanation:

Given;

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distance between 4 nodes, L = 15.0 cm

The wavelength (λ) of the wave is calculated as follows;

Node to Node = λ/2

L = 2(Node to Node) = (4 Nodes) = 2 (λ/2) = λ

Thus, λ = L = 15.0 cm

The speed (v) of the wave is calculated as follows;

v = fλ

v =  10 Hz   x  15.0 cm

v = 150 cm/s

Therefore, the speed of the waves is 150 cm/s

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A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.350s. ignore air resistance.
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Answer:

a. 0.6 m b. 0.385 m c. 3.6 m/s at 287.78° to the horizontal

Explanation:

a. Using s = ut - 1/2gt² for motion under gravity where s = vertical distance = height of table, u = initial vertical velocity of book = 0 m/s, t = time of flight = 0.350 s and g = acceleration due to gravity = 9.8 m/s².

Substituting these these values into s and taking the top of the table as position 0 m, we have.

0 - s = 0t - 1/2gt²

-s = -1/2gt²

s = 1/2gt²

s = 1/2 × 9.8 m/s² × (0.350 s)²

s = 0.6 m

b. Using d = v't where d = horizontal distance from table, v' = horizontal velocity of book = 1.10 m/s and t = time of flight = 0.350 s

d = v't = 1.10 m/s × 0.350 s = 0.385 m

c. Using v² = u² - 2gs where u = initial vertical velocity of book = 0 m/s and g = 9.8 m/s², s = -0.6 m (negative since we are at the bottom and 0 m is at the top)and v = final vertical velocity of book

v² = u² - 2gs

= 0 - 2 × 9.8 m/s² × (-0.6 m)

= 11.76 m²/s²

v = √11.76 m/s

= 3.43 m/s

So, the magnitude of the resultant velocity is V = √(v² + v'²)

= √((3.43 m/s)² + (1.10 m/s)'²)

= √(11.76 m²/s² + 1.21 m²/s²)

= √12.97 m²/s²

= 3.6 m/s

Its direction Ф = tan⁻¹(-v/v') since v is in the negative y direction

= tan⁻¹(-3.43 m/s/1.10 m/s)

= tan⁻¹(-3.1182)

= -72.22°

Ф = -72.22°+ 360 = 287.78° since it is in the third quadrant

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