Answer:
Kinetic energy is energy of motion. Doubling the speed will quadruple the kinetic energy. The relationship between speed and kinetic energy is: This means that the factor by which kinetic energy increases is the square of the factor by which speed or velocity increases for a given object.
Explanation:
At the center of a 50 m diameter circular ice rink, if a 77 kg skater traveling at 2.3
m/s and then collides with a 63 kg skates traveling at 3.7 m/s. This is how
long it will take them to glide to the edge of the rink:
Speed after the collision= √{[77(2.3)77^2]
+ [63(3.7)^2]} / (77+63)=2.09 m/s
For them to be able to get to the edge
which is 50 m away it will take them 23.9
seconds.
The initial velocity of the ball is 0. Applying:
v = u + at
v = 0 + 229 x 0.08
v = 18.3 m/s
a)
Vx = Vcos(∅)
Vx = 18.3cos(52.3)
Vx = 11.2 m/s
b)
Vy = Vsin(∅)
Vy = 18.3sin(52.3)
Vy = 14.5 m/s
To solve the problem it is necessary to apply the equations related to the Poiseuilles laminar flow law, with which the stationary laminar flow ΦV of an incompressible and uniformly viscous liquid (also called Newtonian fluid) can be determined through a cylindrical tube of constant circular section. Mathematically this can be expressed:

Where:
are the viscosities of the concrete before and after the increase
l = Length of the vessel
= Radio of the vessel before and after the increase
= Change in the pressure
The rates of flow before and after he increase
Our values are given as:
10 times her resting rate
95% of its normal value
Increase of 50%
Plugging known information to get







Therefore the factor of average radio of her blood vessels increased is 1.589 the initial factor after the increase.
Answer:
Explanation:
Given
Time taken to reach ground is 
Malda initial velocity 
Let h be the height of Cliff
using 
where, u=initial velocity
t=time
In first case chirpy drop downward thus u=0


For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]
time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by
