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3 years ago

A sum of Rs.5,000 written off as depreciation on furniture has not been debited to depreciation account.

Business

1 answer:

Nonamiya [84]3 years ago

5 0

Answer:

Dr Depreciation Account 5,000

Cr suspense Account 5,000

Explanation:

Based on the information given if the amount of Rs.5,000 which was written off as depreciation on furniture has not yet been debited to depreciation account the appropriate Journal entry to rectify the transaction is :

Dr Depreciation Account 5,000

Cr suspense Account 5,000

(Being to rectify the amount of Depreciation not debited in depreciation account now recorded)

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3 years ago

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2 years ago

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3 years ago

Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 cus

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Answer:

A) Single-server single-phase model (M/M/1).

$\lambda=2.5 \,customers/hour\\\\\mu=6\,customers/hour$

B) The goal is not met, as the average time waiting for service is 5.56 minutes.

C) The new mean service rate is 7.5 customers/hour.

In this case, the average time waiting for service is 4 minutes, so the goal is met.

Explanation:

A) This situation can be modeled as a single-server single-phase model (M/M/1).

The mean arrival rate is 2.5 customers per hour.

$\lambda=2.5 \,customer/h$

The mean service rate is 6 customers per hour, calculated as:

$\mu=\frac{60\, min/h}{10 \,min/customer}=6\, customer/h$

B) The average waiting time for a customer can be expressed as:

$W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda} =\frac{2.5}{6}\frac{1}{6-2.5} =0.417*0.222=0.093\,hours\\\\W_q=0.093\,hours*(60min/h)=5.56 \,min$

The average waiting time is 5.56 minutes, so it is more than the goal of 5 minutes.

C) If the average time spent per customer to 8 minutes, the mean service rate becomes

$\mu=\frac{60\, min/h}{8 \,min/customer}=7.5\, customer/h$

An the average waiting time for the service now becomes:

$W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda} =\frac{2.5}{7.5}\frac{1}{7.5-2.5} =0.333*0.2=0.067\,hours\\\\W_q=0.067\,hours*(60min/h)=4 \,min$

The average time is now 4 minutes, so the goal is achieved.

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3 years ago