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3 years ago

5

Why are Carbon-14 and carbon-12 considered to be isotopes?

1 answer:

zhannawk [14.2K]3 years ago

6 0

Answer: I think it's a don't blame me if it's wrong though

Explanation:

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Dahasolnce [82]

If you can have more than 1 answer then the dependent variable is graphed on the Y-axis and and is usually used for comparison since they are usually the experiment results. If you can only have one answer then the dependent variable is graphed on the y-axis.

8 0

3 years ago

2Li+2H2O—>2LiOH+H2

taurus [48]

Explanation:

2Li+2H2O—>2LiOH+H2

Calculate the mass of reacted lithium when H2 is 6.02 * 10 ^ 23 molecules.

I really need the answer with all the calculation please.

3 0

3 years ago

Indigenous rocks form by the cooling and hardening of melted rock.* True False

salantis [7]

Answer: True

Explanation: They are formed by the cooling and hardening of molten magma

3 0

3 years ago

What is the volume, in liters, of 4.00 moles of methane gas, CH4, at 13 ∘C and 1.20 atm?

dimulka [17.4K]

Answer:

78.268L

Signifigant figures = 78L

6 0

3 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o

Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

$Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}$

Now, we are able to solve for m:

$m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} } = 9.70*10^4 g Na=97 Kg Na$ =97 000 g Na

7 0

3 years ago

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