Answer:
Ionic bond
Explanation:
The magnesium atom gives up 2 electrons to form a magnesium ion, Mg2+ . The two electrons are transferred to fluorine atoms to form two fluoride ions, F–.
The frequencies expressed in inverse seconds are 5 s⁻¹ and 1 s⁻¹.
<h3>
What is frequency?</h3>
Frequency is the number of complete cycles in a second made by a wave.
F = 1/T
F = n/t
<h3>When n = 5</h3>
F = 5/s = 5 s⁻¹ = 5Hz
<h3>When n = 1</h3>
F = 1/s = 1 s⁻¹ = 1Hz
Learn more about frequency here: brainly.com/question/254161
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Answer:
The answer is 2.03
Explanation:
The pH of a solution can be found by using the formula
![pH = - log [ {H}^{+} ]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7BH%7D%5E%7B%2B%7D%20%5D)
where H+ is the Hydrogen ion concentration
From the question we have
We have the final answer as
<h3>2.03 </h3>
Hope this helps you
Answer:
It's explained below.
Explanation:
An everyday situation is when we raise an object.
Now, when we raise an object, energy is transferred to the Earth object system and thus the gravitational field energy of the system will increase.
Now, this energy is usually released when the object falls. The mechanism of this release is known as gravitational force.
In the same manner, two magnetic and electrically charged objects that are interacting at a distance will exert forces on each other and this can lead to transfer of energy between the interacting objects.
Answer:
A) E° = 4.40 V
B) ΔG° = -8.49 × 10⁵ J
Explanation:
Let's consider the following redox reaction.
2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)
We can write the corresponding half-reactions.
Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq) E°red = 1.36 V
Anode (oxidation): 2 Li(s) → 2 Li⁺(aq) + 2 e⁻ E°red = -3.04
<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>
The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.
E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V
<em>B) Calculate the free energy ΔG° of the reaction.</em>
We can calculate Gibbs free energy (ΔG°) using the following expression.
ΔG° = -n.F.E°
where,
n are the moles of electrons transferred
F is Faraday's constant
ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J
