Answer:
Explanation:
The pressure, the volume and the temperature of an ideal gas are related to each other by the equation of state:
where
p is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the absolute temperature
For the gas in this problem:
n = 2.00 mol is the number of moles
V = 17.4 L is the gas volume
p = 3.00 atm is the gas pressure
is the absolute temperature
Solving for R, we find the gas constant:
Answer:
5.5 L
Explanation:
Step 1: Given data
- Initial volume (V₁): 6.5 L
- Initial pressure (P₁): 840 mmHg
- Initial temperature (T₁): 84 °C
- Final pressure (P₂): 760 mmHg (standard pressure)
- Final temperature (T₂): 273.15 K (standard temperature)
Step 2: Convert T₁ to Kelvin
We will use the following expression.
K = °C + 273.15
K = 84 °C + 273.15 = 357 K
Step 3: Calculate the final volume of the gas
We will use the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 840 mmHg × 6.5 L × 273.15 K / 357 K × 760 mmHg = 5.5 L
Given:
The density of air = 1.19 g/L at 25°C and atmospheric pressure,
or
density = 1.19 x 10⁻³ kg/L
Volume of air in the room is
V = 12.5*19.5*6.0 = 1462.5 ft³
Note that
1 ft³ = 28.317 L
Therefore
V = (1462.5 ft³)*(28.317 L/ft³) = 4.1414 x 10 ⁴ L
By definition, mass = density*volume.
Therefore, the mass is
(1.19 x 10⁻³ kg/L)*(4.1414 x 10⁴ L) = 49.283 kg
Answer: 49.3 kg (nearest tenth)
Concrete. it cant be any other choice
