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kifflom [539]
3 years ago
13

Why pressure above the surface is greater than in the air​

Physics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels. ... Since most of the atmosphere's molecules are held close to the earth's surface by the force of gravity, air pressure decreases rapidly at first, then more slowly at higher levels.

Explanation:

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When is the ideal time to take a resting heart rate? O A. After exercise OB. After a meal OC. Hirst thing in the morning D. Befo
stira [4]

Answer:

D

Explanation:

7 0
3 years ago
What is the kinetic energy of a 145 g baseball moving at 42 m/s?
klio [65]
Answer:
Kinetic energy = 127.89 Joules

Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
m is the mass = 145 g = 0.145 kg
v is the velocity = 42 m/sec

Substitute in the above equation to get the kinetic energy as follows:
KE = (0.5)(0.145)(42)^2
Kinetic energy = 127.89 Joules

Hope this helps :)
8 0
3 years ago
4. What instrument is used to measure mass?​
givi [52]

Answer:

A Beam balance (or Beam scale) is a device to measure weight or mass.

Explanation:

8 0
3 years ago
Question 1 of 10
Hoochie [10]

Answer:

The neutron is a subatomic particle, symbol 

n

 or 

n0

, with no electric charge and a mass slightly greater than that of a proton. Protons and neutrons constitute the nuclei of atoms. Since protons and neutrons behave similarly within the nucleus, and each has a mass of approximately one atomic mass unit, they are both referred to as nucleons.[6] Their properties and interactions are described by nuclear physics.

Explanation:

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5 0
3 years ago
The angular acceleration of a wheel is given in rad/s2 by 32 t 3 - 11t 4, where t is in seconds. if the wheel starts from rest a
disa [49]

Answer:

t=3.64s

Step by step explanation

Step 1

In this step we use the definition of acceleration to determine the expression to integrate. Note that the acceleration is the derivative of velocity with respect to time.

a=\frac{dv}{dt} \\\implies adt=dv\\\implies dv=(32t^3-11t^4)dt

Step 2

Perform  integration on the expression from step 1. This calculation is performed as shown below.

v=\int(32t^3-11t^4)dt\\v=\frac{32}{4}t^4- \frac{11}{5}t^5 +c\\\8t^4- \frac{11}{5}t^5 +c

Step 3

In this step we use the condition that at t=0, the velocity v=0 to find the exact form of the velocity function. We substitute  this point into the velocity function we found in step 2.

0=8(0)^4-\frac{11}{5} (0)^5+c\\\implies c=0

Step 4

We now  use the function in step 3  to find out when the velocity is zero again.

v=0=8t^5-\frac{11}{5}t^4\\\implies 0=8t^4-\frac{11}{5} t^5\\\implies t^4(8-\frac{11}{5} t)\\\implies t=0, 8-\frac{11}{5}t=0\\\\\implies t=0,t=\frac{40}{11} =3.64

The velocity is zero again when t=3.64

8 0
3 years ago
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