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Citrus2011 [14]
3 years ago
15

Determine whether each of the examples represents a colligative property or a non-colligative property. boiling point elevation

Choose... color Choose... freezing point depression Choose... vapor pressure lowering Choose... density Choose...
Chemistry
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

boiling point elevation - colligative property

color - non-colligative property

freezing point depression - colligative property

vapor pressure lowering - colligative property

density - non-colligative property

Explanation:

A colligative property is a property that depends on the number of particles present in the system.

Freezing point depression, boiling point elevation and vapour pressure lowering are all colligative properties of solutions.

Colour and density do not depend on the number of particles present hence they are not colligative properties.

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shtirl [24]

Answer:

1.Mg+O2.......MgO2

Explanation:

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3 years ago
How many grains are in spaghetti
MissTica

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6 0
3 years ago
QUESTION 21 The combustion of ammonia in the presence of excess oxygen yields NO 2 and H 2O: 4 NH 3 (g) 7 O 2 (g) 4 NO 2 (g) 6 H
Harrizon [31]

Answer:

The answer to your question is 47.44 g of Oxygen

Explanation:

Data

mass of Ammonia = 14.4 g

mass of Oxygen = ?

Balanced chemical reaction

                 4NH₃  +  7O₂  ⇒  4NO₂  +  6H₂O

Process

1.- Calculate the molar mass of Ammonia

NH₃ = 4[(1 x 14) + (3 x 1)] = 4[14 + 3] = 4[17] = 68 g

2.- Calculate the molar mass of Oxygen

O₂ = 7[16 x 2] = 7[32] = 224 g

3.- Use proportions to calculate the mass of Oxygen

                     68g of NH₃ --------------------- 224 g of O₂

                      14.4 g of NH₃ -----------------  x

                       x = (14.4 x 224) / 68

                       x = 3225.6/ 68

                       x = 47.44 g

5 0
3 years ago
What is the formal charge on the xenon atom (xe) in xef2?
Likurg_2 [28]
F  is a    group  17   element  which  are  referred  to  as halogens.  hence  requires  one  electrons   to  obtain  octet    electron  configuration.Therefore F  has  -1  charge.  Xe  is  a  group  18  element  which  are  referred  to  as    noble  gas  which  has  octet  electron  configuration but due  to  the two  F-   Xe   has  +2   formal  charges.
5 0
4 years ago
A/1 * B/C = D
Anit [1.1K]

Answer: 0.64 Moles of Propane

Explanation:

Data:

        Moles of Carbon  =  1.5 mol

        Conversion factor  =  7 mol C produces = 3 mol of Propane

Solution:

            As we know,

               7 moles of Carbon produces =  3 moles of Propane

Then,

           1.5 moles of Carbon will produce  =  X moles of Propane

Solving for X,

                    X =  (1.5 moles × 3 moles) ÷ 7 moles

                    X  =  0.6428571 moles of Propane

Or rounded to two significant figures,

                    X =  0.64 Moles of Propane

Read more on Brainly.com - brainly.com/question/11464115#readmore

3 0
3 years ago
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