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Citrus2011 [14]
3 years ago
15

Determine whether each of the examples represents a colligative property or a non-colligative property. boiling point elevation

Choose... color Choose... freezing point depression Choose... vapor pressure lowering Choose... density Choose...
Chemistry
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

boiling point elevation - colligative property

color - non-colligative property

freezing point depression - colligative property

vapor pressure lowering - colligative property

density - non-colligative property

Explanation:

A colligative property is a property that depends on the number of particles present in the system.

Freezing point depression, boiling point elevation and vapour pressure lowering are all colligative properties of solutions.

Colour and density do not depend on the number of particles present hence they are not colligative properties.

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Show that, with appropriate coefficients, the two reactions can be summed to give the overall oxidation of SO2 by O2 to give SO3
SIZIF [17.4K]

Answer:

See explanation

Explanation:

We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;

Step 1

2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)

Step 2

2NO(g) + O2(g) -------> 2NO2(g)

So, the overall reaction equation is;

2SO2(g) + O2(g) ------> 2SO3(g)

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3 years ago
A sample of an ideal gas has a mass of 0.311 grams. its volume is 0.225 l at a temperature of 55oc and a pressure of 1.166 atm.
BabaBlast [244]
Use pv=nrT


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3 years ago
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What do all electrolytes have in common?
Lerok [7]
Your answer would be they have mobile ions in solution.
7 0
2 years ago
What is the density of an object that has a mass of 20g and a volume of 10 cc?
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3 years ago
4NH3 (g)+502(g)->6H20g)+4NOg) What is the enthalpy change for this reaction?
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So the energy of the bonds broken is 12x the energy to break a N-H single bond plus 5x the amount of energy to break an O—O double bond (you don’t multiply this by anything because in each O2 molecule there is only one bond).

The energy of the bonds formed is 6*2 = 12 Times the amount of energy for a O-H single bond plus 4 times the amount of energy required to break a N—O double bond.

Subtract energy of bonds broken - energy of bonds formed and this is the change in enthalpy.

To know what type of bond it is, draw the Lewis structure.
7 0
3 years ago
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