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Citrus2011 [14]
3 years ago
15

Determine whether each of the examples represents a colligative property or a non-colligative property. boiling point elevation

Choose... color Choose... freezing point depression Choose... vapor pressure lowering Choose... density Choose...
Chemistry
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

boiling point elevation - colligative property

color - non-colligative property

freezing point depression - colligative property

vapor pressure lowering - colligative property

density - non-colligative property

Explanation:

A colligative property is a property that depends on the number of particles present in the system.

Freezing point depression, boiling point elevation and vapour pressure lowering are all colligative properties of solutions.

Colour and density do not depend on the number of particles present hence they are not colligative properties.

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Suppose that a certain biologically important reaction is quite slow at physiological temperature (37 oC) in the absence of a ca
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Answer:

30 kJ

Explanation:

Arrhenius equation is given by:

k=Aexp(-Ea/RT)\\

Here, k is rate constant, A is Pre-exponential factor, Ea is activation energy and T is temperature.

taking natural log of both side

ln k = ln A - Ea/RT

In Arrhenius equation, A, R and T are constant.

Therefore,

ln\frac{k_2}{k_1} =\frac{Ea_1-Ea_2}{RT}

Ea_1-Ea_2 is the  lowering in activation energy by enzyme,

R = 8.314 J/mol.K

T = 37°C + 273.15 = 310 K

\frac{k_2}{k_1} =1\times 10^5

ln 1\times 10^5 =\frac{Ea_1-Ea_2}{RT}\\{Ea_1-Ea_2} = 11.512 \times 8.314 \times 310\\=29670\ J\\=30\ kJ

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3 years ago
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Answer:

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Explanation:

8 0
2 years ago
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Borax (na2b4o7·10h2o; fw = 381.372 g/mol; density = 1.73 g/ml), a primary standard, was used to standardize a solution of hno3.
SashulF [63]
<span>0.06355391 mol The balanced equation for the reaction is Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O So for each mole of Borax to neutralize, it takes 2 moles of HNO3. Calculate number of moles of Borax 0.2619 g / 381.372 g/mol = 0.0006867 mol Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So 0.0013734 / 0.02161 = 0.06355391 mol</span>
3 0
3 years ago
The structure of cyclopentane-1,2-diol​
Lady bird [3.3K]

Answer: five carbon atoms forms a ring. In adjacent two carbon atoms

An hydroxyl group (-OH) is attached. Molecular formula is

C5H8(OH)2

Explanation:

6 0
2 years ago
Consider the following gas samples: 10. g of hydrogen gas, 10. g of helium gas, 2.5 moles of nitrogen gas, 110. g of carbon diox
Pepsi [2]

Explanation:

As we know ,

One mole of a gas contains 6.023 * 10 ²³ number of atoms .

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

( a ) From the question ,

w = 10 g ,

As we know molecular mass of Hydrogen = 2 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 / 2 = 5 mol

The number of atoms in one molecule of Hydrogen = 2

Hence ,

The number of atoms = 5 * 2 *  6.023 * 10 ²³ = 60.23 * 10 ²³ atoms .

( b )  From the question ,

w = 10 g

As we know molecular mass of helium gas = 4 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 /4 = 2.5 mol

The number of atoms in one molecule of Helium = 1

Hence ,

The number of atoms = 5 * 1 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( c ) From the question ,

moles of nitrogen gas = 2.5 mol

The number of atoms in one molecule of  nitrogen gas = 2

Hence ,

The number of atoms = 2.5 * 2 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( d ) From the question ,

w = 110 g

As we know molecular mass of carbon dioxide gas = 44 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 110 / 44 = 2.5 mol

The number of atoms in one molecule of  carbon dioxide = 3

Hence ,

The number of atoms = 2.5 * 3 *  6.023 * 10 ²³ = 45.17 * 10 ²³ atoms .

( e )

From the question ,

w = 365 g

As we know molecular mass of  sulfur hexafluoride gas = 146 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  =  365 / 146 = 2.5 mol .

The number of atoms in one molecule of sulfur hexafluoride gas = 7

Hence ,

The number of atoms = 2.5 * 7 *  6.023 * 10 ²³ = 105.40 * 10 ²³ atoms .

Hence ,

The order is -

sulfur hexafluoride > Hydrogen > carbon dioxide  > nitrogen gas = helium gas

4 0
3 years ago
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