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GarryVolchara [31]
3 years ago
5

STOP SENDING ME RANDOM LINKS I DONT CARE omg ppl actually need help and all u doing is taking people points this is the 4th time

I posted a question and some bot answered with a link or a troll telling me to do it myself and stealing my stuff I just need help literally thats all ​
Chemistry
2 answers:
nydimaria [60]3 years ago
8 0

Answer:

For real that happens to me too.. Maybe I can help?

Explanation:

Viktor [21]3 years ago
5 0

OMG, So true they do the same legit thing to me too!!!!! I would be SO glad to help, especially if it's an essay! Hook me up!! :)

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Using the VSEPR theory , what would the representation mean A central atom with 2 connected atoms atom with I lone pair of Jone
VLD [36.1K]

Answer:

The molecule has a bent geometry

Explanation:

Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.

Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.

The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.

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A

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Explanation:

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GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g
JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of H_2 gas and 1 mole of Br_2 liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ

Divide the equation by 2.

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

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3 years ago
Which of these contains generic material but is not classified as living?
denis-greek [22]
Viruses are not classified as being alive in because of the fact that they can't reproduce.
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