Answer: Here's the answer hope this helps
Explanation:
Answer:
The answer to your question is 64.02 g of H₂O
Explanation:
Data
Mass of magnesium sulfate hepta hydrated = 125 g
Mass of water = ?
Process
1.- Calculate the molar mass of the salt and the molar mass of water
molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g
mass of H₂O = 2 + 16 = 18 g
2.- Use proportions to calculate the mass of water in the epsom salt
246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O
125 g ------------------------- x
x = (125 x 126)/246
x = 15750/246
x = 64.02 g of H₂O
Explanation:
Scientifically speaking, metals are naturally occurring chemical elements that are typically hard, lustrous, and good conductors of both heat and electricity. Examples include iron, gold, silver, copper, zinc, nickel, etc., but also elements we don't normally think of as metals.
Answer:
it shows the breakdown of the atom
Explanation:
it will show it molecularly
Answer:
Sr would be the limiting reactant
5 moles
Explanation:
Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.
Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.
Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.
From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.
When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.
For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.
