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VMariaS [17]
3 years ago
12

What is the idea behid boyles law​

Chemistry
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

Explanation:

For a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. Or Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.

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If 33.6 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass?21.2% KCl
Lelu [443]
The answer here would be 14.9 %KCl and here is how I can explain why:
33.5g / 225.6g x 100% = 14.9% 
<span>you are looking for % of KCl in the solution, you have to add the mass of the KCl and water to get the total mass of the solution
Hope this helps a lot
</span>

7 0
4 years ago
Of the five salts listed below, which has the highest concentration of its cation in water? assume that all salt solutions are s
Morgarella [4.7K]
Answer is: cobalt(II) hydroxide.
Ksp(lead(II) chromate) = [Pb²⁺][CrO₄²⁻]. [Pb²⁺] = √2,8·10⁻¹³ = 5,3·10⁻⁷ M.<span>
Ksp(cobalt(II) hydroxide) = </span>[Co²⁺][OH⁻]². [Co²⁺] = ∛1,3·10⁻¹⁵ = 1,1·10⁻⁵ M.
Ksp(cobalt(II) sulfide) = [Co²⁺][S²⁻]. [Co²⁺] = √5·10⁻²² = 2,23·10⁻¹¹ M.
Ksp(chromium(III) hydroxide) = [Cr³⁺][OH⁻]³. [Cr³⁺] = √(√1,6·10⁻³⁰) = 3,6·10⁻⁸.
Ksp(silver sulfide) = [Ag⁺]²[S²⁻].


6 0
3 years ago
Convert 600 m to mm.
anzhelika [568]

Answer:

600,000

Explanation:

In order to convert meters or metre to millimeter or millimetre, you must multiply the meter/metre by 1000. (Some countries say meter and others say metre.) Hope it helps! <3

5 0
4 years ago
PLEASE HELP ASAP!!!
tangare [24]
The answer is Single Replacement. 
4 0
3 years ago
Read 2 more answers
What is the percent yield for the reaction below when
kumpel [21]

Answer:

Percent yield of reaction is<em> 150%.</em>

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂      →     2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

                      SO₂          :          SO₃

                        2             :            2

                     9.1              :           9.1

                       O₂            :          SO₃

                        1              :            2

                     2.5             :           2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield  × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

8 0
3 years ago
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