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Irina18 [472]
3 years ago
8

Check whether the given value of x is a solution to the equation.

Mathematics
2 answers:
Tom [10]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

To find this out, all you have to do is plug in the given value to the equation

3x - 1 = 5x + 10

3(-5 1/2) - 1 = 5(-5 1/2) + 10

-17.5 = -17.5

m_a_m_a [10]3 years ago
6 0

Answer

x is not a solution.

Step-by-step explanation:

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How to find the side of a rhombus with given diagonals?
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Suppose r(t) = (et cos t)i + (et sin t)j. Show that the angle between r and a never changes. What is the angle?
tatyana61 [14]

Answer:

Angle = Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

Step-by-step explanation:

Given vector r(t) = e^{t}cost i + e^{t}sint j

As we know that,

velocity vector = v = \frac{dr}{dt}

Implies that

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As acceleration is velocity over time so:

acceleration vector = a = \frac{dv}{dt}

Implies that

vector a =

(e^{t}cost - e^{t}sint - e^{t}sint - e^{t}cost )i + ( e^{t}sint + e^{t}cost + e^{t}cost - e^{t}sint )j

vector a = (-2e^{t}sint) i + ( 2e^{t}cost)j

Now scalar product of position vector r and acceleration vector a:

r. a = . \\

r.a = -2e^{2t}sintcost + 2e^{2t}sintcost

r.a = 0

Now, for angle between position vector r and acceleration vector a is given by:

cosФ = \frac{r.a}{|r|.|a|} = \frac{0}{|r|.|a|} = 0

Ф = cos^{-1}(0) = 0

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4 0
3 years ago
Use intercepts to graph each linear function.<br><br>6x-3y=15​
k0ka [10]

Answer:

<h2>6x-3y=15</h2>

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Slope: 2

y-intercept: (0,−5)

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values.

x y

0 −5

5/2 0

Graph the line using the slope and the y-intercept, or the points.

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x y

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Step-by-step explanation:

Hope it is helpful....

7 0
3 years ago
Read 2 more answers
How would i graph y=2/5x+3
AysviL [449]

Answer:

start at 0,0 on a line graph and go up 2 and over 1/2 for you first dot and then

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Step-by-step explanation:

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