Hydrocarbon tells you that it is a <span>six carbon compound containing a triple bond.</span>
Answer:
2.22 g/L
Explanation:
There's a relationship using the ideal gas law between molar mass and density:
, where MM is the molar mass, d is the density, R is the gas constant, T is the temperature, and P is the pressure.
We know from the problem that MM = 32.49 g/mol, T = 458 Kelvin, and P = 2.569 atm. The gas constant, R, in terms of the units atm and Kelvin is 0.08206. Let's substitute these values into the formula:


Solve for d:
d * 0.08206 * 458 K = 32.49 * 2.569
d = (32.49 * 2.569) / (0.08206 * 458 K) ≈ 2.22 g/L
The answer is thus 2.22 g/L.
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Answer:
30 g
Explanation:
<em>For CaCl₂</em>
3CaCl₂ + 2Na₃PO₄ ⟶ Ca₃(PO₄)₂ + 6NaCl
Moles of CaCl₂ = <em>c</em>×<em>V</em> = 5.0 × 10⁻² × 2.0 = 0.100 mol
Moles of Na₃PO₄ = 0.100 × 2/3 = 0.0667 mol
Mass of Na₃PO₄ = 0.0667 × 163.94 = 10.9 g
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<em>For Mg(NO₃)₂
</em>
3Mg(NO₃)₂ + 2Na₃PO₄ ⟶ Mg₃(PO₄)₂ + 6NaCl
Moles of Mg(NO₃)₃ = <em>c</em>×<em>V</em> = 8.5 × 10⁻² × 2.0 = 0.170 mol
Moles of Na₃PO₄ = 0.170 × 2/3 = 0.113 mol
Mass of Na₃PO₄ = 0.113 × 163.94 = 1 g
—————————————————
Total mass of Na₃PO₄ = 10.9 + 18.6 = 29.5 g
To two significant figures, mass = 30 g
They are far apart from one another and they move around alot