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Maurinko [17]
3 years ago
5

What is the equation of a circle with endpoints of the diameter at (-8, -5) and (-4, 1) ??

Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:(x + 6) + (y + 2)^2 = 13

Step-by-step explanation:

The centre of the circle is halfway along the diameter = (-6, -2)

r^2 = (-4 - -6)^2 + ( 1 - -2)^2 = 2^2 + 3^2 = 13

So circle equation is (x - -6)^2 + (y - -2)^2 = 13

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!!!!Pls help!!!!!
hichkok12 [17]

Answer:

(2,4) is a solution to this system of equations

Step-by-step explanation:

Given system of equation are

y=2x \hfill (1)

y=\frac{-1}{2}x+5\hfill (2)

To find the solution of the given system of equations

To Check that (2,4) is a solution to this system or not

Solving equations (1) and (2)

From equation (1) and y=2x

Now substitute y=2x is equation (2)

2x=\frac{-1}{2}x+5

\frac{-1}{5}x+5-2x=0

5-\frac{x}{2}-2x=0

5-\frac{x+4x}{2}=0

5-\frac{5x}{2}=0

\frac{10-5x}{2}=0

10-5x=0

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x=\frac{10}{5}

Substitute x=2 in equation (1)

y=2x

y=2(2)

Therefore y=4

Therefore the solution is (2,4)

Therefore (2,4) is a solution to the system of equations.

4 0
3 years ago
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geniusboy [140]

Answer:

C

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11 times 11 = 121

11 times 12 equals 132

11 times 13 = 143

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3 and 4! Because 3x4=12 and 4x3= 12! Mark me brainliest so I can help more people !
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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