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Maurinko [17]
3 years ago
5

What is the equation of a circle with endpoints of the diameter at (-8, -5) and (-4, 1) ??

Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:(x + 6) + (y + 2)^2 = 13

Step-by-step explanation:

The centre of the circle is halfway along the diameter = (-6, -2)

r^2 = (-4 - -6)^2 + ( 1 - -2)^2 = 2^2 + 3^2 = 13

So circle equation is (x - -6)^2 + (y - -2)^2 = 13

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In computer technology, a kilobyte is 2^10 bytes in size . A gigabyte is 2^30 bytes in size . The size of a terabyte is the prod
melomori [17]
Kilobyte = 2^10 bytes
gigabyte = 2^30 bytes
terabyte is the product of a kilobyte and a gigabyte....so we multiply

2^10 * 2^30 = 2^(10 + 30) = 2^40 <== a terabyte

** exponent rule : a^b * a^c = a^(b + c)
8 0
3 years ago
Read 2 more answers
The value of y varies directly with x. If x =3, then y=21. What is the value of x when y=105?
Goshia [24]

Answer:

x = 15

Step-by-step explanation:

given that y varies directly with x

mathematically we can express this as

y = k x , where k is a constant

step 1: find k

given x = 3 and y = 21

y = k x

21 = k (3)

k = 7

hence the equation becomes

y = 7 x

when y = 105,

105 = 7x

x = 105 / 7 = 15

3 0
3 years ago
-2 2/3 + (-9 4/5)= ?
Nataly [62]

Answer:

<em>-</em><em>2</em><em>2</em><em> </em><em>/</em><em>3</em><em> </em><em>+</em><em> </em><em>(</em><em>-</em><em>9</em><em>4</em><em>/</em><em>5</em><em>)</em><em> </em>

<em>-</em><em>2</em><em>2</em><em>/</em><em>3</em><em> </em><em>+</em><em> </em><em>-</em><em>8</em><em>9</em><em>/</em><em>5</em>

Step-by-step explanation:

<em>-</em><em>1</em><em>1</em><em>0</em><em>/</em><em>1</em><em>5</em><em> </em><em>+</em><em> </em><em>-</em><em> </em><em>2</em><em>5</em><em>7</em><em>/</em><em>1</em><em>5</em>

<em>-</em><em>3</em><em>6</em><em>7</em><em>/</em><em>1</em><em>5</em>

6 0
3 years ago
Help fast I need real answers thanks
BaLLatris [955]

What is the question?

4 0
3 years ago
Read 2 more answers
If sin Θ = 5/6 , what are the values of cos Θ and tan Θ?
CaHeK987 [17]
For the answer to the question above, I'll provide a solution to my answer below
sin²θ + cos²θ = 1 

<span>so, cos²θ = 1 - (5/6)² => 11/36 </span>

<span>=> cosθ = ±√11/6 </span>

<span>Also, tanθ = sinθ/cosθ => (5/6)/(±√11/6) </span>

<span>i.e. tanθ = ±5/√11 
</span>I hope my answer helped you. Feel free to ask more questions. Have a nice day!
8 0
3 years ago
Read 2 more answers
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