Answer:
This reduces the average force applied during the landing process/ or you can say it reduces the impact your body takes.
Explanation:
Answer:
44.4cm
Explanation:
glass has an index of refraction .n = 1.54
radii of curvature of 40 cm R1 = 40 by
radii of curvature of 600 cm R2 = 60
Now, by lens maker formula
1/f = (n - 1) (1/R1 - 1/R2)
Putting in the given values for n = 1.54 , we get f = 22.2
f = 1 / 0.0225
f = 44.4cm
so, focal length in air will be = 44.4 cm
Answer:
Explanation:
Component of force F₁ in right direction = F₁cos37
= 12 x cos37 = 9.58 N .
Component of force F₂ in vertically upward direction = F₁sin37
= 12 x sin37 = 7.22 N .
a ) Let normal force be R
R + F₁sin37 = mg
R + 7.22 = 1.5 x 9.8 = 14.7
R = 7.48 N .
b )
Net force in horizontal direction = F₂ - F₁cos37
= F₂ - 9.58
This is equal to zero as body is moving with zero acceleration
F₂ - 9.58 = 0
F₂ = 9.58 N
c ) If body is moving with acceleration of 2.5 m /s² along the direction of F₂
F₂ - 9.58 = 1.5 x 2.5 = 3.75
F₂ = 13.33 N .
F= MA
force equals mass time acceleration
250 N = (70 kg ) (A)
250/70 = 3.5 which is about 4 m/s
Hope this helps
False because when the training higher there is less oxygen
