All categories

2 years ago

A) make U subject of the formula E= m/2g(v^2-u^2)

Mathematics

1 answer:

ollegr [7]2 years ago

7 0

Answer:

u = v2−2Egm−−−−−−−√

Step-by-step explanation:

2Eg = 2g (M2g(V2−U2)

2Eg = m(V2 - U2)

2Eg - mV2 - mU2

mU2 = mV2 - 2Eg

mU2m=mV2−2Egm

U2 = mV2−2Egm

= mV2m−2Egm

U2 = V2 - 2Egm

U = V2−2Egm−−−−−−−−√

You might be interested in

The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

Thus solutions of "h" are:

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0

3 years ago

Help please need those answers

icang [17]

We know: The sum of the measures of the angles of a triangle is equal 180°.

We have: m∠A =65°, m∠B = (3x - 10)° and m∠C = (2x)°.

The equation:

65 + (3x - 10) + 2x = 180

(3x + 2x) + (65 - 10) = 180

5x + 55 = 180 subtract 55 from both sides

5x = 125 divide both sides by 5

x = 25

m∠B = (3x - 10)° → m∠B = (3 · 25 - 10)° = (75 - 10)° = 65°

m∠C = (2x)° → m∠C = (2 · 25)° = 50°

<h3>Answer: x = 25, m∠B = 65°, m∠C = 50°</h3>

8 0

3 years ago

Find the radius of a circle that has a circumference of 1671.

son4ous [18]

Answer:

r=8

Step-by-step explanation:

Given formula:

r = C / 2π

It is given that C = 16π

hence

r = 16π / 2π = 8

8 0

2 years ago

HELP ME PLEASE AND THANK YOU

Anna007 [38]

Answer:

The answer is B

Step-by-step explanation:

5 0

2 years ago

GUYS HELP ASAP CHECK THE ATTACHED PHOTO

ASHA 777 [7]

Answer:

As they triangles are congruent, we can say that, angle A = angle O

So, angle A = 105+25 =130

A = 180 - 130 = 50° all angles in a triangle add up to 180)

Soo 50° is the answer,

I'm not too sure about it but I think this is correct, hope this helps, correct me if I'm wrong....

7 0

2 years ago