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3 years ago

Nicole is playing a video game where each round lasts \dfrac{7}{12}

Mathematics

1 answer:

ladessa [460]3 years ago

5 0

9514 1404 393

Answer:

6 3/7 rounds

Step-by-step explanation:

(3 3/4 h)/(7/12 h/round) = (15/4)×(12/7) rounds = 45/7 rounds

= 6 3/7 rounds

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Compare 6. 108 to 3 . 106<br> How much bigger is it from each other

vlada-n [284]

3.002
To solve this problem, all you need to do is subtract 6.108-3.106

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3 years ago

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Write an equivalent expression by distributing the "_" sign outside the parentheses: -k - (-6.2m+1)

nevsk [136]

Answer:

-k + (6.2m - 1)

Step-by-step explanation:

You distribute the negative to everything in the parentheses and change the sign to addition.

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4 years ago

Solve the equation for X.<br> 5/6x - 1/3 = -2

Semmy [17]

Answer:

x = -2

Step-by-step explanation:

First, add 1/3 to both sides. You end up with 5/6x = -5/3. Next, you divide both sides by 5/6. You should finish with x = -2.

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3 years ago

Carla saw a license plate

vladimir1956 [14]

Answer:

Step-by-step explanation:

Comment

Since you make no other restrictions, the numbers can have duplicates.

9 + 9 + 2 is one possibility.

9 + 7 + 4 is another

9 + 8 + 3

and another 33 possibilities. Surely you are not expected to list them all. Three should be enough.

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2 years ago

Learn with an example<br> Find the instantaneous rate of change of k(x) = x at x = 9.

Mrac [35]

Answer:

$k^{\prime}(9) = 1$ .

Step-by-step explanation:

The expression $k(x) = x$ is equivalent to $k(x) = x^{1}$ .

Apply the power rule of differentiation. For any constant $a$ :

$\displaystyle \frac{d}{dx}[x^{a}] = a\, x^{a-1}$ .

In $k(x) = x^{1}$ , $a = 1$ . Thus:

$\begin{aligned}k^{\prime}(x) &= \frac{d}{dx}[x^{1}] \\ &= 1\, x^{1 - 1} \\ &= x^{0} \\ &= 1 && \text{given that $x \ne 0$}\end{aligned}$ .

In other words, the instantaneous rate of change of $k(x)$ (with respect to $x$ ) is constantly $1$ at all $x \ne 0$ .

Therefore, for $x = 9$ , instantaneous rate of change of $k(x)$ (with respect to $x$ ) would be $1$ .

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3 years ago