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frozen [14]
3 years ago
8

1) All cars are blue. (2) All pigs have wings. Therefore, (3) All buses have three wheels. Question 2 options: Passes the true p

remises test and passes the proper form test. Passes the true premises test and fails the proper form test. Fails the true premises test and passes the proper form test. Fails the true premises test and fails the proper form test. None of the above.
Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0

Answer:

Fails the true premises test and fails the proper form test

Explanation:

A valid argument must pass the true premises test and the proper form test.

True premises test checks to see if what the premises is saying is true about the world, example- pigs do not have wings and so the argument fails the true premises test. Proper form test assumes the premises is true and then checks to see if a valid conclusion was drawn based on the premises(even though it might fail the true premises test and may not be true about the world)

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1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

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\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


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Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

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\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
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