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3 years ago

What's the name of first planet closest to the Sun?

Physics

2 answers:

Stolb23 [73]3 years ago

8 0

Answer:

Mercury

Explanation:

It is the smallest planet in our solar system and closest to the Sun

juin [17]3 years ago

3 0

Mars is the closet to the sun

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How to solve this question? The answer for A is 40kmh-1

Galina-37 [17]

Wish it'll help
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4 years ago

State two ways of velocity

givi [52]

Rapidity of motion or operation; swiftness; quickness. Mech. the rate of motion ; the change of position of a point per unit of time ; the rate of motion in which direction as well as speed is considered.

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3 years ago

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Vladimir [108]

The answer is going to be B

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3 years ago

Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con

Harlamova29_29 [7]

Answer:

a) 0.3 m

b) r = 0.45 m

Explanation:

given,

q₁ = 0.44 n C and q₂ = 11.0 n C

assume the distance be r from q₁ where the electric field is zero.

distance of point from q₂ be equal to 1.8 -r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8-r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8-r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8-r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 = 6 r

r = 0.3 m

<h3>b) zero when one charge is negative.</h3>

let us assume q₁ be negative so, distance from q₁ be r

from charge q₂ the distance of the point be 1.8 +r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8+r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8+r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8+r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 =4 r

r = 0.45 m

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4 years ago

Un auto si muove lungo una strada rettilinea

Valentin [98]

Answer:

Un'auto si muove lungo un percorso rettilineo con velocità variabile come mostrato in figura. Quando l'auto è in possesso di A, la sua velocità è 10 ms-1 e quando è in posizione B, la sua velocità è 20 ms-1. Se l'auto impiega 5 secondi per spostarsi da A a B, trova l'accelerazione dell'auto.

Explanation:

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3 years ago