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kompoz [17]
3 years ago
14

Heat energy always moves from a _ _ _ place to a _ _ _ _ _ _ place. The three methods of heat transfer are?

Physics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:Heat can travel from one place to another in three ways: Conduction, Convection and Radiation.

Explanation:

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Monochromatic light is incident on a metal surface, and electrons are ejected. If the intensity of the light increases, what wil
drek231 [11]

Answer:The rate of ejection of photoelectrons will increase

Explanation:

If the frequency of incident monochromatic light is held constant and its intensity is increased, the rate of ejection of photoelectrons from the metal surface increases with increase in intensity of the monochromatic light. More current flows due to more ejection of photoelectrons.

4 0
3 years ago
Convert 56 kilometers to inches
svlad2 [7]
The conversion for km to inches is:

1km=39370.1in

Now we can solve for 56 km..

56km=39370.1*56
56km=<span> 2204725.6in

Answer=2,204,725.6in</span>
7 0
3 years ago
As part
umka21 [38]

Answer:

Part a)

a = 3.68 m/s^2

Part b)

a = 11.8 m/s^2

Explanation:

Part a)

For force conditions of two blocks we will have

m_1g - T = m_1 a

T - m_2g = m_2 a

now from above equations we have

(m_1 - m_2) g = (m_1 + m_2) a

a = \frac{m_1 - m_2}{m_1 + m_2} g

now we know that

m_1 = \frac{908}{9.8} = 92.65 kg

m_2 = \frac{412}{9.8} = 42 kg

now from above equation we have

a = \frac{92.65 - 42}{92.65 + 42}(9.8)

a = 3.68 m/s^2

Part b)

When heavier block is removed and F = 908 N is applied at the end of the string then we have

F - mg = ma

908 - 412 = 42 a

a = 11.8 m/s^2

8 0
3 years ago
A 75 W lightbulb is being run on a 110 V outlet. Determine the resistance of the lightbulb. Provide a detailed description of th
Sauron [17]
Power is defined as

P = I*V

where I is the current and V is the voltage

Ohm's law gives us the relation betwen Voltage and current in a resistive component

V = I*R ,  Then

P = V² / R

We solve for R,

R = (110 V)²/ 75W =  161.33 ohms
8 0
3 years ago
A tall cylinder contains 20 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
Zanzabum

Answer:

Pressure, P = 3724 Pa

Explanation:

Given that,

Depth of water, h_w=20\ cm =0.2\ m

Depth of oil, h_o=40-20=20\ cm=0.2\ m

The density of water, d_w=1000\ kg/m^3

The densinty of oil, d_o=900\ kg/m^3

We need to find the gauge pressure at the bottom of the cylinder. So, total pressure is equal to :

P=d_wgh_w+d_ogh_o\\\\P=(d_wh_w+d_oh_o)g\\\\P=(1000\times 0.2+900\times 0.2)\times 9.8\\\\P=3724\ Pa

So, the gauge pressure at the bottom of the cylinder is 3724 Pa.

3 0
3 years ago
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