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sweet-ann [11.9K]
3 years ago
12

OMG PLZ PLZ HELP!!

Physics
2 answers:
horsena [70]3 years ago
4 0
1,3,4 I’m pretty sur e
Ede4ka [16]3 years ago
4 0

Answer:

1,4,5 is right

Explanation:

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What is the relation between celsius and kelvin​
Scilla [17]

Answer:

The Celcius and kelvin scale are related unit for unit. One degree unit on the Celcius scale is equivalent to one degree unit on the kelvin scale. The only difference between these two scales is the zero point.

7 0
3 years ago
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â/8.37 points scalcet8 12.2.037. ask your teacher my notes question part points submissions used a block-and-tackle pulley hoist
AnnyKZ [126]
Refer to the diagram shown below.

The hoist is in static equilibrium supported by tensions in the two ropes.

For horizontal force balance, obtain
T₃ cos 50 = T₂ cos 38
0.6428T₃ = 0.788T₂
T₃ = 1.2259T₂             (1)

For vertical force balance, obtain
T₂ sin 38 + T₃ sin 50 = 350
0.6157T₂ + 0.766T₃ = 350     (2)

Substitute (1) into (2).
0.6157T₂ + 0.766(1.2259T₂) = 350
1.5547T₂ = 350
T₂ = 225.124 N
T₃ = 1.2259(225.124) = 275.979

Answer:
T₂ = 225.12 N
T₃ = 275.98 N

4 0
4 years ago
3. A simple way to state Newton’s first law is:
MrRissso [65]

Explanation:

A simple way to state Newton's first law is:

For every action force, there is a reaction force which is equal in magnitude and opposite in direction.

4 0
3 years ago
How do professional bicycle riders reduce friction. Name two ways.<br> Thx
wlad13 [49]
A well maintained bicycle is key.  Oil the chain so that it's less likely to get hung up.  It will have a smoother flow.  Another could be in their clothing.  Notice they usually wear good fitting clothing?  I believe the more from fitting pants help clothing friction.  Another way could be keeping the tires well inflated so that the tires aren't dragging.  Rolling along smoothly on properly inflated tires seems like a must.  Get a few more answers along with mine, so that you have a variety to choose from.
4 0
3 years ago
Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. What will its angul
alexandr402 [8]

Answer:

θ = 225 rad

Explanation:

given data

angle = 25 rad

to find out

angular velocity after 3t?

solution

let angular acceleration α in t

θ = ω × t + 0.5 × α × t²        ........................1

here ω  = 0 (initial velocity )

so put this value here

25 = 0 + 0.5 × α × t²             ..........................2

α = 25 ÷ (0.5 t²)

α = 50 ÷ t²                            .........................3

now here we take in 3t

θ = ω × 3t + 0.5 × α × (3t)²

for ω  = 0

θ = 0 + 0.5 × α × 9t²

now put value in eq 2

so

θ = (0.5) ×  (50 ÷ t²) ×  (3t)²

θ = 25 × 9

θ = 225 rad

6 0
3 years ago
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