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4 years ago

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An object has a kinetic energy of 225 j and a momentum of magnitude 28.3 kg · m/s. (a) find the speed of the object. m/s (b) fin

d the mass of the object

1 answer:

Irina18 [472]4 years ago

5 0

A. hope this helps ;0

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A spherical capacitor contains a charge of 3.00 nC when connected to a potential difference of 230 V. If its plates are separate

Assoli18 [71]

Answer:

Part(a): the capacitance is 0.013 nF.

Part(b): the radius of the inner sphere is 3.1 cm.

Part(c): the electric field just outside the surface of inner sphere is $\bf{2.81 \times 10^{4}~n~C^{-1}}$ .

Explanation:

We know that if 'a' and 'b' are the inner and outer radii of the shell respectively, 'Q' is the total charge contains by the capacitor subjected to a potential difference of 'V' and ' $\epsilon_{0}$ ' be the permittivity of free space, then the capacitance (C) of the spherical shell can be written as

$C = \dfrac{4 \pi \epsilon_{0}}{(\dfrac{1}{a} - \dfrac{1}{b})}~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

Part(a):

Given, charge contained by the capacitor Q = 3.00 nC and potential to which it is subjected to is V = 230V.

So the capacitance (C) of the shell is

$C &=& \dfrac{Q}{V} = \dfrac{3 \times 10^{-90}~C}{230~V} = 1.3 \times 10^{-11}~F = 0.013~nF$

Part(b):

Given the inner radius of the outer shell b = 4.3 cm = 0.043 m. Therefore, from equation (1), rearranging the terms,

$&& \dfrac{1}{a} = \dfrac{1}{b} + \dfrac{1}{C/4 \pi \epsilon_{0}} = \dfrac{1}{0.043} + \dfrac{1}{1.3 \times 10^{-11} \times 9 \times 10^{9}} = 31.79\\&or,& a = \dfrac{1}{31.79}~m = 0.031~m = 3.1~cm$

Part(c):

If we apply Gauss' law of electrostatics, then

$&& E~4 \pi a^{2} = \dfrac{Q}{\epsilon_{0}}\\&or,& E = \dfrac{Q}{4 \pi \epsilon_{0}a^{2}}\\&or,& E = \dfrac{3 \times 10^{-9} \times 9 \times 10^{9}}{0.031^{2}}~N~C^{-1}\\&or,& E = 2.81 \times 10^{4}~N~C^{-1}$

3 0

3 years ago

A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did

dezoksy [38]

Answer:

t = 5 s

Explanation:

Data:

Initial Velocity (Vo) = 7 m/s
Acceleration (a) = 3 m/s²
Final Velocity (Vf) = 22 m/s
Time (t) = ?

Use formula:

$\boxed{t=\frac{Vf - Vo}{a}}$

Replace:

$\boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}$

Solve the subtraction of the numerator:

$\boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}$

It divides:

$\boxed{t=5\ s}$

How much time did it take the car to reach this final velocity?

It took a time of <u>5 seconds.</u>

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3 years ago

A scientist that applies the laws of science to the needs of communities is called _____.

s2008m [1.1K]

Answer:

The experimental scientist

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3 years ago

The mass of 150cm³ of stone is 400g. its density is

WITCHER [35]

Answer:2.67kgm/s cube

Explanation: density = mass ÷ volume = 400 ÷ 150

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The coordinates of a bird flying in the xy plane are given by x(t)=αt and y(t)=3.0m−βt2, where α=2.4m/s and β=1.2m/s2

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We've seen this introduction to a question posted several times before here on Brainly, but it always stops right there. What is the question ? ? ?

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