The answer is False, they are not always correct
<span>a decrease in the distance between the earth and the moon</span>
Recall this kinematic equation:
a =
This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).
a is the acceleration.
Vi is the initial velocity.
Vf is the final velocity.
Δt is the amount of elapsed time.
Given values:
Vi = 0 m/s (the car starts at rest).
Vf = 25 m/s.
Δt = 10 s
Substitute the terms in the equation with the given values and solve for a:
a =
<h3>a = 2.5 m/s²</h3>
Answer:
<h2><em>Potential energy.</em></h2>
Explanation for yall who dont get:
Basically, the energy that is changing during a phase change is potential energy. Why? Cuz, during a phase change, the heat added (Potential Energy INCREASES) or released (Potential Energy DECREASES) allow the molecules to move apart or be together.
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<em>Leme know if im wrong. </em>
<em>GL.</em>
Answer:
Approximately , assuming that .
Explanation:
Let denote the time required for the package to reach the ground. Let and denote the initial and final height of this package.
.
For this package:
- Initial height: .
- Final height: (the package would be on the ground.)
Solve for , the time required for the package to reach the ground after being released.
.
.
Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at .) From calculations above, the package would travel forward at that speed for about . That corresponds to approximately:.
Hence, the package would land approximately in front of where the plane released the package.