If the perimeter of a square measures 32 cm, each side measures 32/4= 8 cm, because all sides are equal.
The diagonal that passes through the center of the square divides the square into two triangles. The triangles are formed by a <u>hypotenuse </u>(the diagonal, which is k in this case), <u>and two sides,</u> that measure 8 cm each, in this case.
Because of Pythagoras' theorem, we know that the <u>lenght of the hypotenuse</u> (in this case the hypotenuse is k) equals the squared root of the sum of the squared sides, which in this case can be expressed as .
Given width is 24 less than length. W=L-24 Perimeter = 2(W+L)=2(L-24+L)=4L-48 But we're also given perimeter = 172' Therefore 4L-48=172 solve for L 4L=172+48=220 L=55' W=55-24 = 31' Check: Perimeter = 2(W+L)=2(31+55)=2*86=172' good!
Answer: The dimensions of the garden are 31' * 55'
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