Ask question

Ask question

All categories

3 years ago

8

baseball player hits a line drive estimated to have traveled 145 meters the ball leaves the bat with a horizontal velocity of 40

.0 m/s . how much time was the ball in the air

1 answer:

Amanda [17]3 years ago

8 0

Answer:

5800

Explanation:

caluculatior

You might be interested in

What sort of trade-offs do you think engineers make between functionality, safety, and aesthetics when building a real bridge?

skelet666 [1.2K]

They make sure the bridge is functional and safe before the add the
<span>aesthetics</span>

5 0

3 years ago

Read 2 more answers

the word default refers to which of the following a special mode for making changes to a single object the standard layout use f

nirvana33 [79]

Answer:

The standard layout use for new files flat surfaces. etc.

4 0

3 years ago

A small first-aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of t

Artyom0805 [142]

Answer:

D = 30.625 m

Explanation:

given,

Speed of the climber = 1.3 m/s

time = 2.5 s

acceleration due to gravity = 9.8 m/s²

initial speed of the kit = 1.3 m/s

velocity of the kit after 2.5 s

using equation of motion

v = u + a t

v = 1.3 + 9.8 x 2.5

v = 25.8 m/s

distance travel by the kit in 2.5 s

v² = u² + 2 g h

25.8² = 1.3² + 2 x 9.8 x h

19.6 h = 663.95

h = 33.875 m

distance travel by the rock climber in 2.5 s

distance = speed of climber x time

h' = 1.3 x 2.5

h' = 3.25 m

Distance between kit and rock climber

D = h - h'

D = 33.875 - 3.25

D = 30.625 m

The kit is 30.625 m below climber.

8 0

3 years ago

An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standar

defon

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency $\zeta$ = 3%

where;

$\zeta = \dfrac{W_{out}}{Q_{supplied }}$

$Q_{supplied } = \dfrac{2}{0.03} \ MW$

$Q_{supplied } = 66.66 \ MW$

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

$LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}$

Also;

$\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K$

$\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K$

$LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}$

$LMTD = \dfrac{8}{In (5)}$

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

$Q_H = UA (LMTD)$

where;

U = overall heat coefficient given as 1200 W/m².K

$66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\ A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\ \mathbf{A = 11178.236 \ m^2}$

The mass flow rate:

$Q_{H} = mC_p(T_{in} -T_{out} ) \\ \\ 66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{ 66.667 \times 10^6}{4.18 \times 8} \\ \\ \mathbf{m = 1993630.383 \ kg/s}$

3 0

3 years ago

A source emits a sound and is represented by the red dot in this map. Four people are located around the source, and the circles

xenn [34]

Answer:

Explanation:

When a sound is produced by a stationary point source , moving waves are produced around it in circles consisting of compression and rarefaction . These compression and rarefaction are mutually equidistant. But when the source moves in a particular direction , waves get compressed in that direction . If in a distance of V , n number of waves are formed , in case of moving source , same no of waves will lie in V - v distance in the direction of motion. . Here V is velocity of sound , v is velocity of source and n is no of waves being produced per second. So we see that distance between two consecutive waves becomes smaller . Or , waves get compressed . In this region frequency becomes greater.

A is standing left of source and source is moving towards left , hence A. will hear highest pitch or greatest frequency.

4 0

3 years ago