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what are valence shell electrons?a. electrons thata re unchargedb. electrons that are positively chargedc. electrons that are av

goblinko [34]

Your answer is c. electrons that are available for bonding.

6 0

3 years ago

What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?

DiKsa [7]

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

$2\mu t + \frac{\lambda}{2} = \Delta x$

so here we can say that for maximum intensity condition we will have

$\Delta x = N\lambda$

so we have

$2\mu t + \frac{\lambda}{2} = N\lambda$

now for visible wavelength we have

for N = 1

$2\mu t = \frac{\lambda}{2}$

$\lambda = 4\mu t$

$\lambda = 4(\frac{4}{3})(390 nm)$

$\lambda = 2080 nm$

for N = 2

$\lambda = \frac{4\mu t}{3}$

$\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}$

$\lambda = 693.3 nm$

for N = 3

$\lambda = \frac{4\mu t}{5}$

$\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}$

$\lambda = 416 nm$

6 0

4 years ago

8. A boy pulls a 20.0-kg box with a 140-N force at 30° above a horizontal surface. If the coefficient of kinetic friction betwee

LenaWriter [7]

0.280 m is the correct answer

8 0

3 years ago

2 kids are running down the hall at 2 m/s, one is 40kg and the other is 50kg (p=ma)

Georgia [21]

The net force acting on the two (2) kids is equal to 180 Newton.

<u>Given the following data:</u>

Mass of kid 1 = 40 kilogram.

Mass of kid 2 = 50 kilogram.

Acceleration = 2 $m/s^2$

To determine the net force acting on the two (2) kids:

First of all, we would calculate the total mass of the two (2) kids:

$Total\;mass = 50+40$

Total mass = 90 kg.

<h3>How to calculate net force.</h3>

In this exercise, you're required to calculate the magnitude of the net force that is acting on these two (2) kids running down the hall. Thus, we would apply Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by this formula;

$Net\;force = mass \times acceleration$

Substituting the given parameters into the formula, we have;

$Net\;force = 90 \times 2$

Net force = 180 Newton.

Read more on acceleration here: brainly.com/question/1121817

7 0

3 years ago

Find the x-component of this

Sholpan [36]

Answer: 74.8m

Explanation:

We have the vector defined by:

r = 101m

θ = 42.2°

When we want to write this as rectangular components, we have that:

x = r*cos(θ)

y = t*sin(θ)

this is because we can construct a triangle rectangle, where the module of the vector is the hypotenuse, the x component is the adjacent cathetus and the y component is the opposite cathetus.

Then, here we have that the x component is

x = 101m*cos(42.2°) = 74.8m

5 0

3 years ago