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Zolol [24]
3 years ago
7

According to a newspaper account, a paratrooper survived a training jump from 1200 ft when his parachute failed to open but prov

ided some air resistance by ï¬apping unopen in the wind. allegedly he hit the ground at 100 mi/h after falling 8 seconds. test the accuracy of this account.
Physics
1 answer:
Schach [20]3 years ago
7 0
<span>Let's make a few assumptions. 1. The paratrooper's lowest speed will be just prior to impact. 2. Since the jump was from a relatively low altitude, the paratrooper used a static line and the parachute should have opened almost immediately upon jumping. So let's convert 100 mi/h to ft/s 100 mi/h * 5280 ft/mi / 3600 s/h = 146.67 ft/sec Given the 1st assumption above, the MAXIMUM distance the paratrooper would have fallen would be 8 seconds at 146.67 ft/s, so 8 s * 146.67 ft/s = 1173.36 ft The calculated distance is close to the jump distance, which agrees with both assumptions 1 and 2. So this account does seem reasonable. Additionally, looking for the speed of a parachutist doing a freefall in the belly-to-earth position with arms and legs outspread, they will generally reach a terminal velocity of 120 mi/h which is slightly faster than the 100 mi/h in the article. This too is in agreement with the defective parachute flapping and causing some extra air resistance.</span>
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Explanation:

Given parameter;

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Unknown:

The degree celcuis temperature at 45mm = ?

Solution:

To solve this problem we simply compare the mm- scale to the celcius - scale that we know.

The upper fixed point is the boiling point of water

Lower fixed point is the freezing point of water

This shows that both the upper and lower fixed point of both thermometers are the same;

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Solving;

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3 years ago
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3 years ago
Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point. F⃗ 1F→1F_1_vec has a magnitude of 9.20 NN and is directed at an a
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To obtain the x component of the resultant force, first we have to know the x components of the other forces. To do this, we just have to do some trigonometry:

|F_{1x}|=|F_1|\cos\theta_1=9.20N\cos62.0\°=4.31N \\|F_{2x}|=|F_2|\cos\theta_2=5.00N\cos53.6\°=2.96N

Since both vectors are in the left side of the y-axis, they have a negative x component. So:

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