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slava [35]
3 years ago
5

How much heat is needed to rise the temperature by 10 oc of mass 5kg if substance of specific heat capacity 300j/kg of What is t

hermal of a substance
Physics
1 answer:
Umnica [9.8K]3 years ago
4 0

Answer: 15000 J

Explanation:

Given ;

Temperature change, dθ = 10

Mass of substance, m = 5 kg

Specific heat capacity, C = 300 j/kg°C

Quantity of heat, Q required is obtained using the relation ;

Q = mCdθ

Q = 5kg * 300 j/kg°C * 10°C

Q = 5 * 300 J * 10

Q = 15000 J

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babunello [35]

Answer:

While a body is said to be in motion if it changes its position with respect to immediate surroundings.

A body is said to be in uniform motion if it covers equal distances in equal interval of time.

A body is said to be in non-uniform motion if it covers unequal distances in equal interval of time or vice-versa

4 0
2 years ago
Explain how buoyancy can defeat the force of gravity​
Olenka [21]

Answer:

Buoyancy causes things to float in water or liquid which appears to defeat the force of gravity. Hope this helps.

7 0
3 years ago
When a certain string is clamped at both ends, the lowest four resonant frequencies are 50, 100, 150, and 200 Hz. When the strin
mario62 [17]

Answer:

Explanation:

Given

Lowest four resonance frequencies are given with magnitude

50,100,150 and 200 Hz

The frequency of vibrating string is given by

f=\frac{n}{2L}\sqrt{\frac{T}{\mu }}

where n=1,2,3 or ...n

L=Length of string

T=Tension

\mu =Mass per unit length

When string is clamped at mid-point

Effecting length becomes L'=0.5 L

Thus new Frequency becomes

f' =\frac{n}{L}\sqrt{\frac{T}{\mu }}

i.e. New frequency is double of old

so new lowest four resonant frequencies are 100,200,300 and 400 Hz      

4 0
2 years ago
The figure shows a 1 cm cube that has a mass of 1 gram. Calculate the density of the cube in kg/m³.
dolphi86 [110]
Density = 1 g/cm^3 = 1000 Kg/m^3
3 0
3 years ago
A sonar pulse sent out by a boat arrives back after 4 seconds. If the speed of sound in water is 1600m/s, how deep is the water?
Varvara68 [4.7K]

Answer:

the boat would be deeped by 3200 m

Explanation:

Given that

The boat arrives back after 4 seconds

And, the speed of the sound in water is 1,600 m/s

We need to find out how much deep is the water

So,

As we know that

Distance = ( speed × time) ÷ 2

Here we divided by 2 because the boat arrives back

= (1600 × 4) ÷ 2

= 3200 m

Therefore the boat would be deeped by 3200 m

7 0
3 years ago
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