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Kobotan [32]
3 years ago
8

Impure compounds tend to have lower melting points than pure samples. Explain why this occurs, using biphenyl as an example. Mak

e sure you consider what happens upon melting in molecular terms. (b) Is recrystallization a suitable method for purifying all types of organic compounds? If not, why not?
Chemistry
1 answer:
Oduvanchick [21]3 years ago
5 0

Explanation:

(a)

Substances with impurity melts at lower temperature and this phenomenon is called depression in melting point.  

Pure solid organic compounds or inorganic compounds tend to have highly packed structure. When a substance melts, these arrangements are disturbed. Impurities disrupt the regular arrangement of the crystals. Therefore, If impurities are present within the crystals, less energy are required to disturb the crystal, therefore, melts at lower temperature.

(b)

Recrystallization is not a suitable method for the purification of all organic compounds.

In recrystallization, organic compounds are dissolved in a suitable solvent at high temperature. After that solution is cooled slowly. During cooling process, the crystals of organic compound separate from the solution and impurities are left in the solution.

So, finding a suitable solvent for a solid organic compound is difficult. Moreover, liquid organic compounds cannot be purified by this method.

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Iodine 131, cesium 137, and strontium 90 are all considered isotopes. What are isotopes?
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Answer:

Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.

Explanation:

If the number of protons had changed then it would just be a different element.

Electron number changing simply adds charge to the atom, and doesn't change it or anything.

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Balanced symbol equation for reaction between sodium carbonate solution and dilute sulphuric acid?
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Answer:

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Calculate the pOH of a 0.0143 M NaOH solution at 25 ⁰C.
arsen [322]

Answer:

A.) 1.845

Explanation:

You can find the pOH using the following equation:

pOH = -log[OH⁻]

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2 years ago
For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f
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Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

(c) 4f. n =4. Sublevel f, l = 3. Number of orbitals = 7

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

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3 years ago
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