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An equal-tangent vertical curve is to be constructed between grades of -2% (initial) and 1% (final). The PVI is at station 110 0

Mila [183]

Answer:

The curve length (<em>L</em>) will be = 1218 ft

The elevations and stations for PVC and PVI

a. station of PVC = 103 + 91.00

b. station of PVI = 116 + 09.00

c. elevation of PVC = 432.18ft

d. elevation of PVI = 426.09ft

Explanation:

First calculate for the length (<em>L</em>)

To calculate the length, use the formula of "elevation at any point".

where, elevation at any point = 424.5.

and ∴ PVC Elevation = (420 + 0.01L)

Then, calculate for Station of PVC and PVI and elevation of PVC and PVI

4 0

3 years ago

A 240 V, 60 Hz squirrel-cage induction motor has a full-load slip of 0.02 and a full-load speed of 1764 rpm. The winding resista

earnstyle [38]

Answer:

full load current = 7.891151 A

so correct option is b. Ir= 7.89

Explanation:

given data

Energy E = V = 240 V

frequency = 60 Hz

full-load slip = 0.02

full-load speed = 1764 rpm

winding resistance = 0.6 Ω

winding reactance = 5 Ω

to find out

rotor current at full-load

solution

we will apply here full load current formula that is express as

full load current = $\frac{S*E}{\sqrt{R^2+ (S*X)^2}}$ ...................1

here S is full-load slip and E is energy given and R is winding resistance and X is winding reactance

put here value we get

full load current = $\frac{0.02*240}{\sqrt{0.6^2+ (0.02*5)^2}}$

full load current = 7.891151 A

so correct option is b. Ir= 7.89

6 0

3 years ago

Rewrite the following loops, using the enhanced for an array of floating-point numbers. Write your code within comments

dmitriy555 [2]

Answer:

Explanation:poop

4 0

3 years ago

How much will it cost to train the entire company to use a recycling program if the training includes paper handouts? (Remember,

bezimeni [28]

Answer:

With the current budget of $1,000, it is possible to train the company and buy 3 recycling carts given that recycling pickup within the area is free

Explanation:

The office waste management budget that is not being spent = $1,000

The given expense parameters are;

The training cost per hour per employee = $12.00

The number of people in the entire company = 45

The cost of preparing the training material per hour = $20.00

The number of people to create the training material = 3 people

The time it will take each person in creating the training material = 3 hours

The cost of recycling cart = $80.00 per cart

The cost of paper handouts per employee = $0.05

The cost of materials include;

The total cost for the training = $12.00 × 45 = $540

The cost for the handout = $0.05 × 45 = $2.25

The cost of preparing the materials = $20.00 × 3 × 3 = $180.00

The total costs of the training = $540 + $4 + $180.00 = $724

The amount available to buy cart = $1,000 - $724 = $276

Therefore;

The amount available to buy cart = $276

The number of carts that can be bought = 276/80 = 3.45 carts

Therefore, we round down to get;

The number of carts that can be bought = 3 carts

8 0

3 years ago

An urn contains r red, w white, and b black balls. Which has higher entropy, drawing k ~2 balls from the urn with replacement or

svetlana [45]

Answer:

The case with replacement has higher entropy

Explanation:

The complete question is given:

'Drawing with and without replacement. An urn contains r red, w white and b black balls. Which has higher entropy, drawing k ≥ 2 balls from the urn with replacement or without replacement?'

Solution:

- n drawing is the same irrespective of whether there is replacement or not.

- X to denotes drawing from an urn with r red balls, w white balls and b black balls. So, n = b + r + w.

We have:

p_X(cr) = r / n

p_X(cw) = w / n

p_X(cb) = b / n

- Now, if Xi is the ith drawing with replacement then Xi are independent and p_Xi (x) = pX(x) for x e ( cr , cb , cw ).

- Now, let Yi be the ith drawing with replacement where Yi are not independent p_Yi (x) = pX(x) for x ∈ X.

- To see this, note Y1 = X and assume it is true for Yi and consider Yi+1:

p_Y(i+1) (cr) = p(Y(i+1),Yi).(cr, cr) + p(Y(i+1),Yi).(cr, cw) + p(Y(i+1),Yi).(cr, cb)

= r*( r - 1 )/n*(n-1) + w*r/n*(n-1) + b*r/n*(n-1) = r / n = p_X(cr)

- This means, using the chain rule and the conditioning theore m:

H(Y1, Y2, . . . , Yn) = H(Y1) + H(Y2|Y1) + H(Y3|Y2, Y1) + ... H(Yn|Yn−1, . . . , Y1)

=< SUM H(Yi) = n*H(X) = H(X1, X2, . . . , Xn)

- with equality if and only if the Yi were independent:

H(Y1, Y2, . . . , Yn) < H(X1, X2, . . . , Xn)

Answer: The case with replacement has higher entropy

4 0

3 years ago