PV=nRT n=PV/RT
R=.0821 atm x L
Mol x K
T=318K
P=.55atm
V=37.4L
n= (.55atm) (37.4L) /
.0821atm x L (318k)
mol x K
n= .79 mol of sulfur dioxide
Answer:
Matter is classified into two broad categories, namely, pure substances and mixtures. Mixtures can be separated into pure substances by physical methods. Pure substances are further divided into categories as elements and compounds. ... A pure substance can be either an element or a compound.
Explanation:
Answer:
% yield = 82.5%
Explanation:
HgO + 2Cl₂ → HgCl₂ + Cl₂O
Our reactants are:
Our products are:
We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.
Percent yield = (Yield produced / Theoretical yield) . 100
Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:
% yield = (0.71 g/0.86g) . 100 = 82.5%
Answer:
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