The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.
<h3>How do we calculate grams from moles?</h3>
Grams (W) of any substance will be calculated by using their moles (n) through the following equation:
M = molar mass
And moles of the gas will be calculated by using the ideal gas equation as:
P = pressure = 1atm
V = volume = 40L
n = moles = ?
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 200K
On putting these values on the above equation, we get
n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles
- Now grams of hydrogen gas will be calculated by using the first equation as:
W = (2.44mol)(2g/mol) = 4.88g
Hence required mass of hydrogen gas is 4.88g.
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Answer:
69,632 grams
explanation
number of molecules =mass\molemass
nh3 14 +2×3=20
3.4×1024=m/20
cross multiply
grams =69,632
Explanation:
2.04 % hydrogen
32.65% sulphur
65.31% is oxygen
atomic ratio
hydrogen =2.04÷1=2.04
sulphur =32.65÷32=1.02
oxygen =65.31÷16=4.08
simplest ratio
hydrogen = 2.04÷1.02=2
sulphur =1.02÷1.02=1
oxygen =4.08÷1.02=4
empirical formula is H2SO4
