I hope this helps you
take both of sides paranthesis square
(2a+7b)^2=(11)^2
4a^2+2.4a.7b+49b^2=121
4a^2+49b^2+56.2=121
4a^2+49b^2=9
Answer:
x = (c + 6b)/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-b + 3x = c + 5b
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add <em>b</em> to both sides: 3x = c + 6b
- Divide 3 on both sides: x = (c + 6b)/3
A question:
(5.3 x 10 to the 6th power) + 8.2 10 to the 6th power)
A solution:
Multiply 10 x 10 6 times to get rid of the two powers.
(5.3 x 1,000,000) + (8.2 x 1,000,000)
Multiply inside the parenthises.
(5,300,000) + (8,200,000)
Add:
13,500,000.
A answer:
13, 500,000.
B question:
(6.5 x 10 to the 7th power) / (5 x 10 to the 3rd power)
B solution:
Again, get rid of the powers.
(6.5 x 10,000,000) / (5 x 1,000)
Multiply inside the parenthesis:
(65,000,000) / (5,000)
Divide:
13,000
B answer:
13,000.
C question:
(4.6 x 10 to the 6th power) (3 x 10 to the 5th power) / (2 x 10 to the 7th power)
C solution:
Get rid of powers:
(4.6 x 1,000,000) (3 x 100,000) / (2 x 10,000,000)
Multiply:
(4,600,000) (300,000) / (20,000,000)
multiply in the left side:
(1,380,000,000,000) / (20,000,000)
divide:
69,000
C answer:
69,000
Answer:
4(x-6)(x-1) = 0
Standard form: 4x^2-28x+24=0
Step-by-step explanation:
First, let's write an equation where the roots are 6 and 1.
To do that, we can use the intercept form <em>a(x-p)(x-q) = 0</em>, where <em>a</em> is the leading coefficient, and <em>p </em>and <em>q</em> are the roots.
We can therefore plug what we know into this equation:
4(x-6)(x-1) = 0
