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Tamiku [17]
3 years ago
9

A 40.0 liter gas tank contains 70.0 moles of hydrogen gas. What would be the volume of the tank which could hold 50.0 moles of h

ydrogen gas at the same temperature and pressure
Chemistry
1 answer:
Leokris [45]3 years ago
6 0

Answer:

V_2=28.6L

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to solve this problem via the Avogadro's gas law as a way to understand the volume-moles behavior as a directly proportional relationship:

\frac{V_2}{n_2}=\frac{V_1}{n_1}

In such a way, we solve for the final volume as shown below:

V_2=\frac{V_1n_2}{n_1} \\\\V_2=\frac{40.0L*50.0mol}{70.0mol}\\\\V_2=28.6L

Regards!

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Explanation:

<u>Step 1</u>: Data given

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This means every mole C3H8

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