Answer:
Sodium iodide NaI
Magnesium chloride MgCl₂
Explanation:
Silicon dioxide SiO₂ it is not soluble in water, so it can not be recrystallized from water, it is a white solid and the boiling point is 2230 °C. This one is not the unknown solid.
Sodium iodide NaI it is soluble in water, it has a white color and the boiling point is 1304 °C
. This can be the unknown solid.
Magnesium chloride MgCl₂ is soluble in water, it have a white color and the boiling point is 1,412 °C
. This can be the unknown solid.
Phosphorus tribromide PBr₃ is will start a hydrolysis reaction in water, it is a colorless liquid and it has a boiling point of 173 °C. This one is not the unknown solid.
[Ar] 3d2 4s2 is the answer i believe
To calculate the amount of the compound in the units of grams, we need to first obtain for the molar mass of the compound. We calculate as follows:
MgCl2 = <span>24.31 + (2 x 35.45) = 95.21 g/mol
</span><span>340 g MgCl2 ( 1 mol / 95.21 g ) = 3.57 mol MgCl2
Hope this answers the question. Have a nice day.</span>
Take the molar mass of lithium from your periodic table and multiply it by 3.5 moles
