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Marrrta [24]
2 years ago
13

A circular test track for cars has a circumference of 4.7 km. A car travels around the track from the southernmost point to the

northernmost point. What distance does the car travel? What is the car's displacement from its original position?
Physics
1 answer:
Alika [10]2 years ago
7 0
Well, for the distance traveled, the car goes from the northernmost point to the southernmost point. So, it travels half of the circle's circumference = 4.7/2 = 2.35 km.

For the displacement, by going from the northernmost point to the southernmost point, the car basically just travels the diameter of circle.

So, using the formula: Circumference = 2πr = <span>πd

Hence, the d = C/</span>π = 4.7/<span>π = 1.49605... = 1.5 km (2 significant figures)
Therefore, displacement = 1.5 km</span>
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(a) 1200 rad/s

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where we have

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(b) 25 s

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\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

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t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s

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