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Marrrta [24]
3 years ago
13

A circular test track for cars has a circumference of 4.7 km. A car travels around the track from the southernmost point to the

northernmost point. What distance does the car travel? What is the car's displacement from its original position?
Physics
1 answer:
Alika [10]3 years ago
7 0
Well, for the distance traveled, the car goes from the northernmost point to the southernmost point. So, it travels half of the circle's circumference = 4.7/2 = 2.35 km.

For the displacement, by going from the northernmost point to the southernmost point, the car basically just travels the diameter of circle.

So, using the formula: Circumference = 2πr = <span>πd

Hence, the d = C/</span>π = 4.7/<span>π = 1.49605... = 1.5 km (2 significant figures)
Therefore, displacement = 1.5 km</span>
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A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
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<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

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        Time, t = 6.8 s    

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     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

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     Substituting

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Its velocity when it crosses the finish line is 117.65 m/s

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