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Marrrta [24]
3 years ago
13

A circular test track for cars has a circumference of 4.7 km. A car travels around the track from the southernmost point to the

northernmost point. What distance does the car travel? What is the car's displacement from its original position?
Physics
1 answer:
Alika [10]3 years ago
7 0
Well, for the distance traveled, the car goes from the northernmost point to the southernmost point. So, it travels half of the circle's circumference = 4.7/2 = 2.35 km.

For the displacement, by going from the northernmost point to the southernmost point, the car basically just travels the diameter of circle.

So, using the formula: Circumference = 2πr = <span>πd

Hence, the d = C/</span>π = 4.7/<span>π = 1.49605... = 1.5 km (2 significant figures)
Therefore, displacement = 1.5 km</span>
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Approximately \displaystyle\rm \left[ \begin{array}{c}\rm191\; m\\\rm-191\; m\end{array}\right].

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The question assumes that the skier is in a free-fall motion. In other words, the skier travels with a constant horizontal velocity and accelerates downwards at g (g \approx \rm -9.81\; m\cdot s^{-2} near the surface of the earth.) At t seconds after the skier goes beyond the edge of the ramp, the position of the skier will be:

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To eliminate t from this expression, solve the equation between t and x for t. That is: express t as a function of x.

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Replace the t in the equation of y with this expression:

\begin{aligned} y = &-\frac{9.81}{2}\cdot t^{2}\\ &= -\frac{9.81}{2} \cdot \left(\frac{x}{30.556}\right)^{2}\\&= -0.0052535\;x^{2}\end{aligned}.

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The value of y can be found by evaluating either equation at this particular x-value: x = 190.35.

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