Question

A constant net force that has a magnitude of 135.5 N is exerted on a 26.7 kg object that is initially not moving. a. Draw a free body diagram of the object. Assume there is only the net force of 135.5 N acting on the object.
b. What acceleration does this force produce?
c. Sketch a position vs. time graph for the object.
d. Sketch a velocity vs.. time graph for the object.
e. How far does the the object travel in 8.82 s?

Answer 1

Explanation:

Given that,

Net force = 135.5 N

Mass = 26.7 kg

(a). We need to draw a free body diagram

A force is exerted on a object.

(b). We need to calculate the acceleration

Using formula of acceleration

$a =\dfrac{F}{m}$

$a=\dfrac{135.5}{26.7}$

$a=5.07\ m/s^2$

(c). We need to draw the sketch a position vs. time graph for the object.

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times5.07\times t^2$

$s=2.535 t^2$

(d). We need to draw the sketch a velocity vs. time graph for the object.

Using equation of motion

$v = u+at$

Put the value into the formula

$v=0+5.07t$

$v =5.07 t$

(e). We need to calculate the distance travel in 8.82 s

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

$s=0+\dfrac{1}{2}\times5.07\times(8.82)^2$

$s=197.20\ m$

Hence, This is the required solution.