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eimsori [14]
3 years ago
5

A 6 kg bowling ball moves with a speed of 3 m/s. How fast does a 7 kg bowling ball need to move so that it has the same kinetic

energy?
Physics
1 answer:
maw [93]3 years ago
4 0

Answer: 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy.

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{1}{2}mv^2

m = mass of object

v= velocity of the object

K.E=\frac{1}{2}\times 6kg\times (3m/s)^2=27Joules

b) for a 7 kg bowl to have kinetic energy of 27 Joules:

27J=\frac{1}{2}\times 7kg\times v^2

v^2=7.7

v=2.8m/s

Thus 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy

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Because the object is still made of the same material 
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7 0
3 years ago
A sample of a gas has a volume of 639 cm3 when the pressure is 75.9 kPa. What is the volume of the gas when the pressure is incr
const2013 [10]

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

7 0
4 years ago
An electric current is flowing through a long cylindrical conductor with radius a. The current density J is uniform in the cylin
RUDIKE [14]

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

4 0
3 years ago
Which term below describes a measurement of how hard an object pushes against a surface?
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I hope the answer is D. Pressure

8 0
3 years ago
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Elliot jumps up and down on a pogo stick. He weighs 600.N, and his pogo stick has a spring with spring constant 1100N/m. What is
tia_tia [17]

From conservation of energy, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

The given weight of Elliot is 600 N

From conservation of energy, the total mechanical energy of Elliot must have been converted to elastic potential energy. Then, the elastic potential energy from the spring was later converted to maximum potential energy P.E of Elliot.

P.E = mgh

where mg = Weight = 600

To find the height Elliot will reach, substitute all necessary parameters into the equation above.

250 = 600h

Make h the subject of the formula

h = 250/600

h = 0.4167 meters

Therefore, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

Learn more about energy here: brainly.com/question/24116470

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3 years ago
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