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eimsori [14]
3 years ago
5

A 6 kg bowling ball moves with a speed of 3 m/s. How fast does a 7 kg bowling ball need to move so that it has the same kinetic

energy?
Physics
1 answer:
maw [93]3 years ago
4 0

Answer: 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy.

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{1}{2}mv^2

m = mass of object

v= velocity of the object

K.E=\frac{1}{2}\times 6kg\times (3m/s)^2=27Joules

b) for a 7 kg bowl to have kinetic energy of 27 Joules:

27J=\frac{1}{2}\times 7kg\times v^2

v^2=7.7

v=2.8m/s

Thus 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy

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seraphim [82]

Answer:

\theta = 15^o \: or\: 75^o

Explanation:

As we know that the formula of range is given as

R = \frac{v^2sin2\theta}{g}

now we know that

maximum value of the range of the projectile is given as

R_{max} = \frac{v^2}{g}

now we need to find such angles for which the range is half the maximum value

so we will have

\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}

sin(2\theta) = \frac{1}{2}

2\theta = 30 or 150

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7 0
3 years ago
The current in a hair dryer measures 15 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?
ZanzabumX [31]
We have that there is a formula connecting these three. V=I*R where V is voltage, I is the current and R is the resistance. Substituting, we get that V=210 Volta, which is the unit of measurement for voltage. You can think of the relationship in the following way : The energy of the field is equal to the flow of the field times the resistance that it meets.
6 0
3 years ago
A closely wound circular coil has a radius of 6.00 cmand carries a current of 2.65 A. How many turns must it have if the magneti
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Answer:

Given:

radius of the coil, R = 6 cm = 0.06 m

current in the coil, I = 2.65 A

Magnetic field at the center, B = 6.31\times 10^{4} T

Solution:

To find the number of turns, N, we use the given formula:

B = \frac{\mu_{o}NI}{2R}

Therefore,

N = \frac{2BR}{\mu_{o}I}

N = \frac{2\times 6.31\times 10^{4}\times 0.06}{4\pi \times 10^{- 7}\times 2.65}

N = 22.74 = 23 turns (approx)

 

8 0
3 years ago
A block of mass, m, sits on the ground. A student pulls up on
kakasveta [241]

Answer a

Explanation: a

3 0
3 years ago
Please help! I’ll give brainliest! :)
jeka94

Answer:

C.) Gravity

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2 years ago
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