Ask question

Ask question

All categories

Norma-Jean [14]

3 years ago

6

What is warmer 0 f or 0 c

2 answers:

Yuliya22 [10]3 years ago

8 0

Answer:

Zero Celsius is freezing and corresponds to 32 deg Farenheit. Zero Fahrenheit is therefore 32 deg F lower than Zero Celsius. 0 Fahrenheit is colder.

so I think 0*C

Explanation:

I'm not sure! :P

Vanyuwa [196]3 years ago

6 0

0 degree C
Explanation:
0 degree C = 32 degree F
0 degree F = -17.7778 degree C

You might be interested in

A ball is thrown horizontally at 20 m/s from the top of a cliff 50 meters high. how far from the base of the cliff does the ball

Oksanka [162]

You need to divide the motion into its component: vertical and horizontal motion.

The time taken to fall vertically from the cliff is equal to the time taken to move horizontally.

Using the vertical component, which is an accelerated motion with an initial velocity equal to zero, we can solve for t:
h = 1/2 · g · t²

t = √(2·h / g)
= √(2·50 / 9.8)
= 3.2 s

Horizontally, it is a constant motion:
d = v · t
= 20 · 3.2
= 64 m

The ball will strike the ground at a distance of 64 meters from the cliff.

6 0

3 years ago

A magnetic field would be produced by a beam of

Oksi-84 [34.3K]

<span>A magnetic field would be produced by a beam of (3) protons.
Although you could easily make a case for any of these four options (the question is pretty ambiguous), there can be only one correct answer, which is the third option, in this case.
</span>

7 0

4 years ago

A 15.7 kg block is dragged over a rough, horizontal surface by a constant force of 83.1 N

Kay [80]

Answer:

The work done by the 83.1 N force is 4687.5 J.

The magnitude of the work done by the force of friction is 1187.5 J.

Explanation:

Given:

Mass of the block, $m=15.7$ kg

Force acting on it, $F=83.1$ N

Angle of application of force, $\theta = 25.7$ °

Displacement of the block, $d=62.6$ m

Coefficient of friction, $\mu =0.161$

Acceleration due to gravity, $g=9.8$ m/s²

Work done by a force is given as:

$Work,W=F\times d\times \cos\theta$

So, work done by the constant force is given as:

$W_{force}=83.1\times 62.6\times \cos(25.7)\\W_{force}=4687.5\textrm{ J}$

Now, in order to find work done by friction, we need to evaluate friction.

For the vertical direction, the net force is zero as there is no vertical motion.

Therefore,

$N + F\sin\theta = mg\\ N = mg-F\sin\theta$

Frictional force is given as:

$f=\mu N=\mu (mg-F \sin \theta)=0.161\times ((15.7\times 9.8)-(83.1\times \sin(25.7))=18.97\textrm{ N}$

Now, friction acts in the direction opposite to the displacement. Thus, angle between frictional force and displacement is 180°.

Therefore, work done by friction is:

$W_{fric}=f\times d\times \cos\theta_f\\W_{fric}=12.72\times 62.6\times \cos(-180)\\W_{fric}=18.97\times 62.6\times -1\\W_{fric}=-1187.5\textrm{ J}$

Negative sign indicates that frictional force is acting opposite to motion.

So, the magnitude of the work done by the force of friction is 1187.5 J.

8 0

4 years ago

Which of the following takes place in the combustion chamber of a gas turbine engine?A. A glow plug is used to add enough heat t

erica [24]

Answer:

Fuel oil is mixed with a proper portion of compressed air

Explanation:

A gas turbine has three main part, which are

combustion chamber
air compressor
power turbine

The combustion chamber is responsible for mixing fuel with a proper portion of compressed air.

The air compressor supplies air in sufficient quantity to satisfy the requirements of the combustion chamber

The power turbine produces the power to drive the air compressor.

6 0

4 years ago

The kinetic energy, k, of an object varies jointly with the mass of the object and the square of the velocity of the object. a 5

o-na [289]

Answer:

KE = 1/2 M V^2 = 1/2 * 25 * 10^2 = 1250 J

Check

M2 = 1/2 M1

V2 = V1 / 2

E2 = 1/2 * 1/4 E1 = E1 / 8 = 10000 / 8 = 1250 J

8 0

2 years ago

Read 2 more answers