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DENIUS [597]
3 years ago
8

How much mass should be attached to a vertical ideal spring having a spring constant (force constant)of 39.5 N/m so that it will

oscillate at 1.00 Hz?A) 39.5 kgB) 2.00 kgC) 1.00 kgD) 1.56 kgE) 6.29 kg
Physics
1 answer:
nordsb [41]3 years ago
6 0

Answer:

m = 1 kg

Explanation:

Given that,

The force constant of the spring, k = 39.5 N/m

The frequency of oscillation, f = 1 Hz

The frequency of oscillation is given by the formula as formula as follows :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} \\\\f^2=\dfrac{k}{4m\pi^2}\\\\m=\dfrac{k}{4\pi^2 f^2}\\\\m=\dfrac{39.5}{4\pi^2 \times (1)^2}\\\\m=1\ kg

So, the mass that is attached to the spring is 1 kg.

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Answer:

1.35208 m/s

Explanation:

Speed of the boat = 0.75 m/s

Distance between the shores = 100 m

Time = Distance / Speed

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Time taken by the boat to get across is 133.33 seconds

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Speed = Distance / Time

Speed=\frac{150}{\frac{100}{0.75}}=1.125\ m/s

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From Pythagoras theorem

c=\sqrt{0.75^2+1.125^2}\\\Rightarrow c=1.35208\ m/s

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4 0
3 years ago
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steposvetlana [31]

Answer:

The average velocity of the sled is vavg = s/t.

Explanation:

Hi there!

The average velocity is calculated as the traveled distance over time:

vavg = Δx/Δt

Where:

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Δx = traveled distance.

Δt = elapsed time.

We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:

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6 0
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BRAINLEST FOR CORRECT ANSWER
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Answer:

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