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DiKsa [7]
3 years ago
6

The frequency of a wave is 560 Hz. What is it’s period

Physics
1 answer:
Crazy boy [7]3 years ago
4 0
The answer would be, "1/560 seconds".
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The atomic mass number of copper is A=64. Assume that atoms in solid copper form a cubic crystal lattice. To envision this, imag
Stells [14]

Answer:

<em>0.228 nm</em>

<em></em>

Explanation:

Atomic mass number of copper = 64

but an atomic mass unit = 1.66 x 10^-27 kg

therefore, the mass of the copper atom m = 64 x 1.66 x 10^-27 kg = 1.06 x 10^-25 kg

The number of atoms in this mass n = ρ/m

where ρ is the density of copper = 8.96 x 10^3 kg/m^3

==> n = (8.96 x 10^3)/(1.06 x 10^-25) = 8.45 x 10^28 atoms/m^3

We know that the volume occupied by this amount of atoms n = a^{3}

where a is the lattice constant

equating, we have

8.45 x 10^28 = a^{3}

a = 4.389 x 10^9

we also know that

d =  1/a

where d is the smallest distance between the two copper atom.

d = 1/(4.389 x 10^9) = 2.28 x 10^-10 m

==> <em>0.228 nm</em>

5 0
3 years ago
The steel ball in a pinball game rolls around a flat, tilted surface. If you flick the ball straight uphill, it gradually slows
Brilliant_brown [7]
Why: As the steel ball rolls uphill, the velocity gradually decreases and finally the ball stops, thus, the acceleration will be in the opposite direction of motion (that is downhill). After the stop, the ball will start rolling downhill by an increasing velocity, thus, the acceleration in this case will be in the same direction as the motion (downhill again).
7 0
3 years ago
What is the radius of the 5th orbital in hydrogen?
iren2701 [21]

Answer:

So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.

Explanation:

pls mark me brainless hope this helps loves x!

6 0
2 years ago
Read 2 more answers
A teacher will never give a student any additional information about a test in a one-on-one meeting because it would not be fair
laila [671]

Answer:

False

Explanation:

5 0
3 years ago
Read 2 more answers
An object-spring system undergoes simple harmonic motion with an amplitude A. Does the total energy change if the mass is double
son4ous [18]

Answer: No, The energy will remain the same

Explanation: Doubling the mass and leaving the amplitude unchanged won't have any effect on the total energy of the system.

At maximum displacement, E=0.5kA^2

Where E = total energy

K = spring constant

A = Amplitude

From the formula above : Total Energy is independent of mass,. Therefore, total energy won't be affected by Doubling the mass value of the object.

Also when the object is at a displacement 'x' from its equilibrium position.

E = Potential Energy(P.E) + Kinetic Energy(K.E)

P.E = 0.5kx^2

Where x = displacement from equilibrium position

E = Total Energy

K. E= E-0.5kx^2

From the relation above, total energy is independent of its mass and therefore has no effect on the total energy.

6 0
4 years ago
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