Let w be the width of the rectangle and y be the length,
then y = 5w - 26. Another equation given is that w times y = 63
The trick is to set this up with two variables and two equations, solve using any method that you know : graphing, substitution, or elimination (also called linear combinations). Maybe you can also see the answer in the two equations?
Answer:
y=4x-8.5
Step-by-step explanation:
Use point- slope form, since you are given one point and one slope.
y-y₁=m(x-x₁)
Plug coordinates and slope in.
y-(-1/2)=4(x-2)
Solve
y+1/2=4x-8
y=4x-8.5
Answer:
There would be 14 cats and 9 dogs
Step-by-step explanation:
In order to find the amount of cats and dogs, we need to set up the system of equations. To do so, start by setting cats as x and dogs as y. Now we can write the first equation to show the total number of animals.
cats + dogs = 23
x + y = 23
Now we can write a second one that shows the difference in the number of cats and dogs.
cats - dogs = 5
x - y = 5
Now we can add the two equations together to solve for x.
x + y = 23
x - y = 5
2x = 28
x = 14
Now that we have the number of cats, we can find the number of dogs by using either equation.
x + y = 23
14 + y = 23
y = 9
So first you figure out what 25% of $40.00 is whitch would be $30.00. Then what i think you would do next is add 6% of the cost of the dress. 6% of $30.00 is $1.80. so $30.00 + $1.80 = $31.80 dollors for the dress.
For this problem plug in the given x and y values:
For the first one: No
second one: No
third one: Yes
fourth one: No