9514 1404 393
Answer:
a) x = -3
b) y = (28/27)x -27
Step-by-step explanation:
a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...
x = constant
For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...
x = -3
__
b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...
m = -1/(-27/28) = 28/27
Using the point-slope equation for a line, we can model Ace Rd as ...
y -y1 = m(x -x1)
y -1 = (28/27)(x -27)
y = (28/27)x -27
I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.
Answer:
xn = n·(n + 1)/2
Step-by-step explanation:
In standard form the two equations are
7x +y = 5
7x +y = -5
The equations describe lines that are parallel.
Answer:
Slope <em>m</em> (Gradient) = 3
y-intercept: (0, -5)
General Formulas and Concepts:
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
y = 3x - 5
<u>Step 2: Break function</u>
Slope <em>m</em> = 3
y-intercept <em>b</em> = -5
