The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?
Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of
to
.
Explanation:
Given: Mass = 500 g
Initial temperature = 
Final temperature = 
The standard value of specific heat of ethyl alcohol is
.
Formula used to calculate the heat energy is as follows.

where,
q = heat energy
m = mass of substance
C = specific heat
= initial temperature
= final temperature
Substitute the values into above formula as follows.
![q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29%5C%5C%3D%20500%20g%20%5Ctimes%202.46%20J%2Fg%5E%7Bo%7DC%20%5Ctimes%20%5B150%20-%20%28-40%29%5D%5E%7Bo%7DC%5C%5C%3D%20233700%20J)
Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of
to
.
Answer:
1.10134 * 10⁻⁹m⁻¹
Explanation:
K = 680Nm⁻¹
μ = ?
μ = (m₁ + m₂) / m₁m₂
compound = CO
C = 12.0 g/mol = 0.012kg/mol
O = 16.0g/mol = 0.016kg/mol
μ = (m₁ + m₂) / m₁m₂
μ = (0.012 + 0.016) / (0.012*0.016) = 145.83
v = 1/2πc * √(k/μ)
ν = 1/ 2*3.142* 3.0*10⁸ * √(630/145.83)
v = 5.30*10⁻¹⁰ * 2.078
v = 1.10134*10⁻⁹m⁻¹
Copernicus's model states that the sun is in the center, and that the planets move around it in a circle. Kepler's first law of planetary motion says that they move around the sun in an ellipse.