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muminat
3 years ago
5

A ball is thrown vertically upward with an initial speed v and reaches a maximum height y1. The same ball is thrown with an init

ial speed 3v to reach the maximum height y2. What is the correct relationship between y2 and y1?
Physics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

y2 = 9y1

Explanation:

According to projectile, the formula for calculating maximum height is expressed as;

Maximum height H = u²/2g

If a ball is thrown vertically upward with an initial speed v and reaches a maximum height y1, then

y1 = v²/2g

2g = v²/y1 ..... 1

If the same ball is thrown with an initial speed 3v to reach the maximum height y2, hence;

y2 = (3v)²/2g

2g = 9v²/y2 ..... 2

Equate 1 and 2

v²/y1 = 9v²/y2

1/y1 = 9/y2

Cross multiply

9y1 = y2

Rearrange

y2 = 9y1

Hence the correct relationship between y2 and y1 is y2 = 9y1

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Two spheres A and B of negligible dimensions and masses 1 kg and √3 kg respectively, are supported on the smooth circular surfac
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Answer:

α = π/3

β = π/6

Explanation:

Use arc length equation to find the sum of the angles.

s = rθ

π/20 m = (0.1 m) (α + β)

π/2 = α + β

Draw a free body diagram for each sphere.  Both spheres have three forces acting on them:

Weight force mg pulling down,

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and tension force T pulling tangential to the surface.

Sum of forces on A in the tangential direction:

∑F = ma

T − m₁g sin α = 0

T = m₁g sin α

Sum of forces on B in the tangential direction:

∑F = ma

T − m₂g sin β = 0

T = m₂g sin β

Substituting:

m₁g sin α = m₂g sin β

m₁ sin α = m₂ sin β

(1 kg) sin α = (√3 kg) sin (π/2 − α)

1 sin α = √3 cos α

tan α = √3

α = π/3

β = π/6

4 0
4 years ago
Which of the following types of pollution is NOT linked to coal-burning power plant emissions?
Vika [28.1K]
A is not linked. Coal burning is not an effect of acid rain.
~Deceptiøn
8 0
3 years ago
A car is traveling at a speed of 50 km/hr. The positive y-axis is north and the positive x-axis is east. Resolve the car's veloc
hjlf
We need to draw a coordinates. the east and south should be the north vector for horizontal line 50 KM in distance is zero. the south is a negative. the south east and north west we should draw the 45 degrees angle in the approprate quadrant and then use the 1-1-sqrt(2) have a relationship in 45-45-90 triangles to resolve the N/S, E/W components.

hope this help
6 0
3 years ago
Once you start pulling your object with less force than friction, what should you expect your object to do? What about when your
forsale [732]

#Case -1

If Pulling force is less than frictional force the object won't move .

#Case-2

If Pulling force is greater than frictional force then object will be .

In order to calculate friction force you need Limiting friction first .

\\ \sf\longmapsto F_L=\mu sN

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8 0
3 years ago
Read 2 more answers
Ignoring air​ resistance, an object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic mode
Lostsunrise [7]

Explanation:

Given that,

An object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic model as :

d=16t^2..........(1)

(a) We need to find the time taken by the object to fall 1148 ft. Put this in equation (1) as :

16t^2=1148

t=\sqrt{71.75}

t = 8.47 seconds

(b) If the object is in free fall for 18.5 sec after it is​ dropped, then the height of the object is given by :

d=16(18.5)^2

d = 5476 ft

Hence, this is the required solution.

7 0
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